1

这是我的 WCF REST OperationContract

 [OperationContract(Name = "SaveBasicInfoObjectById")]
     [WebInvoke(Method = "POST",
          ResponseFormat = WebMessageFormat.Xml,
          RequestFormat = WebMessageFormat.Xml,
         BodyStyle = WebMessageBodyStyle.Bare,
         UriTemplate = "Core/SaveBasicInfoObjectById?ID={ID}")]
     List<Response> SaveBasicInfoObjectById(string ID, BasicClass basicClass);

这是我的客户代码

  string ID= "123";

  MyService.BasicClass basicClass = new MyService.BasicClass();


  string sErrorMsg = "";
  string sResponseStatus = "";
string URLString = "http://localhost:59133/MyService.svc/Core/SaveBasicInfoObjectById?ID=" + ID;


basicClass.FirstName = txt_Fname.Text.Trim();
basicClass.Lastname = txt_Lname.Text.Trim();

var paramContent = Serialize(basicClass);

CreateWebRequest(URLString, paramContent.ToString());

这是序列化方法

    public static string Serialize<T>(T obj)
    {

        var serializer = new System.Xml.Serialization.XmlSerializer(obj.GetType());
        var ms = new MemoryStream();
        serializer.Serialize(ms, obj);
        string retVal = Encoding.Default.GetString(ms.ToArray());
        ms.Dispose();
        return retVal;

    }

这是 CreateWebRequest 方法

    private string CreateWebRequest(string endPoint, string paramContent)
    {
        string result = string.Empty;

        byte[] buffer = Encoding.UTF8.GetBytes(paramContent);
        var myHttpWebRequest = (HttpWebRequest)WebRequest.Create(endPoint);

        myHttpWebRequest.Method = "POST";
        myHttpWebRequest.ContentLength = buffer.Length;
        myHttpWebRequest.ContentType = "text/xml";

        using (var request = myHttpWebRequest.GetRequestStream())
        {
            request.Write(buffer, 0, buffer.Length);
            request.Close();
        }

        var myHttpWebResponse = (HttpWebResponse)myHttpWebRequest.GetResponse();
        using (var reader = new StreamReader(myHttpWebResponse.GetResponseStream(), Encoding.UTF8))
        {
            result = reader.ReadToEnd();
            myHttpWebResponse.Close();
        }


        return result;
    }

*我面临的问题是对象以以下格式序列化，并且当在服务处命中断点时，对象值为空，即 firstname = "" 和 lastname = "" *

<?xml version="1.0"?>
 <BasicClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" ID="0">
<FirstName xmlns="http://tempuri.org/">James</FirstName>
<Lastname xmlns="http://tempuri.org/">Kravis</Lastname>
</BasicClass>

任何人都可以建议为什么会这样吗？

我现在已经将 tempuri 命名空间针对 firstname 和 lastname 元素替换为“”或空，现在这个工作和来自客户端的值现在在服务中收到

以下是序列化方法的更新代码 

public  string Serialize<T>(T obj)
    {
        //System.Xml.Serialization.XmlSerializer x = new System.Xml.Serialization.XmlSerializer(p.GetType());
        var serializer = new System.Xml.Serialization.XmlSerializer(obj.GetType());
        var ms = new MemoryStream();
        serializer.Serialize(ms, obj);
        string retVal = Encoding.Default.GetString(ms.ToArray());
        ms.Dispose();
        return retVal.Replace("xmlns=\"http://tempuri.org/\"", "");
    }

** 更新上述代码 **

public  string Serialize<T>(T obj)
    {
        var serializer = new System.Xml.Serialization.XmlSerializer(obj.GetType());
        var ms = new MemoryStream();
        serializer.Serialize(ms, obj);
        string retVal = Encoding.Default.GetString(ms.ToArray());
        ms.Dispose();
        return retVal;
    }

** 摆脱了替换并找到了阻止将默认命名空间添加到元素的方法 **

public class BasicClass
{
    [XmlElement(Namespace="")]//add namespace as ""
    public string Firstname{get;set;}

    [XmlElement(Namespace="")]//add namespace as ""
    public string Lastname{get;set;}
}

通过执行上述操作，我可以删除默认命名空间并且无需替换

<?xml version="1.0"?>
 <BasicClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" ID="0">
<FirstName>James</FirstName>
<Lastname>Kravis</Lastname>
</BasicClass>
4

1 回答 1

1

默认情况下，WCF 使用 .DataContractSerializer作为其序列化程序，而不是XmlSerializer. 它们产生（并期望）不同的格式，因此您应该更改客户端（使用 DataContractSerializer 而不是 XmlSerializer 序列化您的对象）或服务（将[XmlSerializerFormat]属性应用于操作或服务合同以让 WCF 使用该序列化程序）。

您也不应该替换“xmlns”声明（Serialize<T>方法中的最后一行），因为这样做会改变生成的 XML 的语义。

于 2012-05-16T23:50:19.143 回答