我有两个表格,我想使用UNION
或其他技术将它们显示为单个结果。
该ID
字段与两个表相关。
第二个表缺少一个字段,因此应该从第一个表中假设缺失值。
下面的示例代码有效,但对于大型数据集来说非常慢。
有没有更高效的解决方案?
T1: T2:
+----+-------+--------+ +----+------+
| id | name | town | | id | name |
+----+-------+--------+ +----+------+
| 1 | Alice | London | | 1 | Bob |
| 2 | Alan | Zurich | +----+------+
+----+-------+--------+
期望的结果:
+----+-------+--------+
| id | name | town |
+----+-------+--------+
| 1 | Alice | London |
| 2 | Alan | Zurich |
| 1 | Bob | London |
+----+-------+--------+
示例代码:
with T1 as
(
select * from
(
values
(1,'Alice','London') ,
(2,'Alan','Zurich')
) as t (id,name,town)
), T2 as
(
select * from
(
values
(1,'Bob')
) as t (id,name)
), T2WithTown as
(
select t2.id,t2.name,t1.town from T2
inner join T1 on t2.id=t1.id
)
select id,name,town from T1
union
select id,name,town from T2WithTown