4

我正在尝试编写一个应用程序，每分钟左右将用户的地理位置发送到 MYSQL 数据库。这是我现在拥有的代码，但它不起作用。我需要如何更改它才能使其正常工作？

JS：

<!DOCTYPE html>
<html>
<head>
<script src="js/jquery.js"></script>
</head>

<body>
<script>
setInterval ( "onPositionUpdate()", 10000 );
function onPositionUpdate(position)
            {
                var lat = position.coords.latitude;
                var lng = position.coords.longitude;
                jQuery.ajax({ type: "POST", 
                    url:  "myURL/location.php", 
                    data: 'x='+lat+ '&y='+lng , 
                    cache: false, 
                        });
                        }

            if(navigator.geolocation)
               navigator.geolocation.watchPosition(onPositionUpdate);
            else
                alert("navigator.geolocation is not available");



</script>
</body>
</html>

和 PHP：

<?php
  include 'config.php';

  // database connection
  $conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);

  // new data

  $x = @$_POST['x'];
  $y = @$_POST['y'];
  // query
  $sql = "update locations set x=?, y=? where username = asd";
  $q = $conn->prepare($sql);
  $q->execute(array($x), ($y));
?>

而且我想这不是发送多个变量的正确方法，是吗？Firebug 的控制台向我展示

 missing } after property list
[Break On This Error]   

data: 'x='+lon+'&y='+lat;

当我只使用一个值时，它只会将该变量发布到服务器一次，然后控制台给出：

position is undefined
[Break On This Error]   

var lat = position.coords.latitude;
4

1 回答 1

4

您需要执行以下操作：

var currPosition;
navigator.geolocation.getCurrentPosition(function(position) {
    updatePosition(position);
    setInterval(function(){
        var lat = currPosition.coords.latitude;
        var lng = currPosition.coords.longitude;
        jQuery.ajax({
            type: "POST", 
            url:  "myURL/location.php", 
            data: 'x='+lat+'&y='+lng, 
            cache: false
        });
    }, 1000);
}, errorCallback); 

var watchID = navigator.geolocation.watchPosition(function(position) {
    updatePosition(position);
});

function updatePosition( position ){
    currPosition = position;
}

function errorCallback(error) {
    var msg = "Can't get your location. Error = ";
    if (error.code == 1)
        msg += "PERMISSION_DENIED";
    else if (error.code == 2)
        msg += "POSITION_UNAVAILABLE";
    else if (error.code == 3)
        msg += "TIMEOUT";
    msg += ", msg = "+error.message;

    alert(msg);
}
于 2012-05-16T05:06:07.047 回答