struct timeval start, end, duration;
gettimeofday(&start, NULL);
res = curl_easy_perform(curl);
gettimeofday(&end, NULL);
timersub(&end, &start, &duration);
tm* startTime = localtime(&start.tv_sec);
tm* endTime = localtime(&end.tv_sec);
char buf[64];
strftime(buf, sizeof(buf), "%Y-%m-%d %H:%M:%S", startTime);
char buf2[64];
strftime(buf2, sizeof(buf2), "%Y-%m-%d %H:%M:%S", endTime);
ofstream timeFile;
timeFile.open ("timingSheet.txt");
timeFile << fixed << showpoint;
timeFile << setprecision(6);
timeFile << "Duration: " << duration.tv_sec << "." << duration.tv_usec << " seconds \n";
timeFile << "Start time: " << buf <<"." << start.tv_usec << "\n";
timeFile << "End time: " << buf2 <<"." << end.tv_usec << "\n";
timeFile.close();
当我运行此代码时,我得到以下输出:
Duration: 3.462243 seconds
Start time: 2012-05-15 17:14:07.432613
End time: 2012-05-15 17:14:07.894856
令我困惑的是,持续时间值与开始和结束时间不匹配。这两个日期仅相差微秒。是否有一个原因?
谢谢!