10

当用户按下屏幕上的按钮时,我试图自动将 SMS 消息发送到某个号码。

这是我的代码:

Intent smsIntent = new Intent(Intent.ACTION_SENDTO,
Uri.parse("sms:xxxxxxxxxxx")); 
smsIntent.putExtra("sms_body", "Hello");
startActivity(smsIntent);

xxxxxxx = 电话号码

我有以下权限:

<uses-permission android:name="android.permission.SEND_SMS"></uses-permission>
<uses-permission android:name="android.permission.RECEIVE_SMS"></uses-permission>

当我按下按钮时,它会将我带到另一个屏幕,我可以在其中编辑文本并按下发送。我只是希望它自动执行此过程,而无需将我带到另一个屏幕。由于我已经定义了我的消息,我只想将它发送到一个特定的号码。

而且我不确定我是否将正确的电话号码放在第二行代码中。我必须先把我的国家代码放在那里还是我可以把我的手机号码放在那里就可以了?

谢谢

4

5 回答 5

20

试试这个代码:

 String messageToSend = "this is a message";
 String number = "2121234567";

 SmsManager.getDefault().sendTextMessage(number, null, messageToSend, null,null);

关于号码,您需要输入号码,就好像您是通过电话拨打该号码或以正常方式发送短信一样。

于 2012-05-15T19:21:30.600 回答
3

您也可以使用 Intent 中的构建:

 buttonSendSms_intent.setOnClickListener(new Button.OnClickListener(){

       @Override
       public void onClick(View arg0) {
        // TODO Auto-generated method stub

        String smsNumber = edittextSmsNumber.getText().toString();
        String smsText = edittextSmsText.getText().toString();

        Uri uri = Uri.parse("smsto:" + smsNumber);
        Intent intent = new Intent(Intent.ACTION_SENDTO, uri);
        intent.putExtra("sms_body", smsText);  
        startActivity(intent);
       }});
于 2012-05-15T19:30:17.980 回答
2

试试这个

private static final String SMS_SENT_INTENT_FILTER = "com.yourapp.sms_send";
private static final String SMS_DELIVERED_INTENT_FILTER = "com.yourapp.sms_delivered";

String message = "hey, this is my message";

String phnNo = " " //preferable use complete international number

PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(
                SMS_SENT_INTENT_FILTER), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0, new Intent(
                SMS_DELIVERED_INTENT_FILTER), 0);

SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(phnNo, null, message, sentPI, deliveredPI);
于 2012-05-15T19:26:50.497 回答
2

简单的方法是使用 SmsManager.Telephony。

于 2012-05-15T19:32:02.710 回答
1

首先设置以下权限:

<uses-permission android:name="android.permission.SEND_SMS"/>
<uses-permission android:name="android.permission.INTERNET"/>
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>

然后创建以下活动:

    <?xml version="1.0" encoding="utf-8"?>
    <android.support.constraint.ConstraintLayout xmlns:android="http://schemas.android.com/apk/res/android"
        xmlns:app="http://schemas.android.com/apk/res-auto"
        xmlns:tools="http://schemas.android.com/tools"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        tools:context=".MainActivity">

        <EditText
            android:id="@+id/editText"
            android:layout_width="0dp"
            android:layout_height="wrap_content"
            android:layout_marginEnd="41dp"
            android:layout_marginLeft="41dp"
            android:layout_marginRight="41dp"
            android:layout_marginStart="41dp"
            android:layout_marginTop="43dp"
            android:ems="10"
            android:hint="Enter Phone no"
            android:inputType="textPersonName"
            app:layout_constraintEnd_toEndOf="parent"
            app:layout_constraintStart_toStartOf="parent"
            app:layout_constraintTop_toTopOf="parent" />

        <EditText
            android:id="@+id/editText2"
            android:layout_width="0dp"
            android:layout_height="wrap_content"
            android:layout_marginEnd="37dp"
            android:layout_marginLeft="37dp"
            android:layout_marginRight="37dp"
            android:layout_marginStart="37dp"
            android:layout_marginTop="28dp"
            android:ems="10"
            android:hint="Enter text"
            android:inputType="textPersonName"
            app:layout_constraintEnd_toEndOf="parent"
            app:layout_constraintStart_toStartOf="parent"
            app:layout_constraintTop_toBottomOf="@+id/editText" />

        <Button
            android:id="@+id/button"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_marginBottom="183dp"
            android:text="SEND"
            app:layout_constraintBottom_toBottomOf="parent"
            app:layout_constraintEnd_toEndOf="parent"
            app:layout_constraintStart_toStartOf="parent" />
    </android.support.constraint.ConstraintLayout> 

现在转到您的MainActivity.java文件并添加以下代码:

public class MainActivity extends AppCompatActivity {

    EditText e1, e2;
    Button b1;
    private final static int SEND_SMS_PERMISSION_REQ=1;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        e1=findViewById(R.id.editText);
        e2=findViewById(R.id.editText2);
        b1=findViewById(R.id.button);
        b1.setEnabled(false);


        if(checkPermission(Manifest.permission.SEND_SMS))
        {
            b1.setEnabled(true);
        }
        else
        {
            ActivityCompat.requestPermissions(this, new String[]{Manifest.permission.SEND_SMS}, SEND_SMS_PERMISSION_REQ);
        }
        b1.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String s1=e1.getText().toString();
                String s2=e2.getText().toString();
                if(!TextUtils.isEmpty(s1)&&!TextUtils.isEmpty(s2))
                {

                    if(checkPermission(Manifest.permission.SEND_SMS))
                    {
                        SmsManager smsManager=SmsManager.getDefault();
                         smsManager.sendTextMessage(s1,null,s2,null,null);
                    }
                    else {
                        Toast.makeText(MainActivity.this, "Permission Denied", Toast.LENGTH_SHORT).show();
                    }
                }
                else
                {
                    Toast.makeText(MainActivity.this, "Permission denied", Toast.LENGTH_SHORT).show();
                }
            }
        });

    }

    private boolean checkPermission(String sendSms) {

        int checkpermission= ContextCompat.checkSelfPermission(this,sendSms);
        return checkpermission== PackageManager.PERMISSION_GRANTED;
    }


    @Override
    public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
        switch (requestCode)
        {
            case SEND_SMS_PERMISSION_REQ:
                if(grantResults.length>0 &&(grantResults[0]==PackageManager.PERMISSION_GRANTED))
                {
                    b1.setEnabled(true);
                }
                break;
        }
    }
}

成功地做到了。

于 2018-08-10T03:32:55.663 回答