3

我有不同的选择如何将我的 GUIDS 存储为字符串行。

1. Accessibility|5102d73a-1b0b-4461-93cd-0c024738c19e
2. 5102d73a-1b0b-4461-93cd-0c024738c19e;#5102d73a-1b0b-4461-93cd-0c024733d52d
3. |;#5102d73a-1b0b-4461-93cd-0c024738c19e;#SharePointTag|5102d73a-1b0b-4461-93cd-0c024733d52d
3. Business pages|;#5102d73a-1b0b-4461-93cd-0c024738cz13;#SharePointTag|5102d73a-1b0b-4461-93cd-0c024733d52d

你们能帮我想想如何解析这个标签并最终得到Guids类型的列表吗?也许正则表达式可以在这种情况下有所帮助?

4

4 回答 4

5

看起来您正在使用托管元数据、术语库 ID 和术语集 ID :)

只需使用常规正则表达式(下面的“p”变量):

string c1 = "Accessibility|5102d73a-1b0b-4461-93cd-0c024738c19e";
string c2 = "5102d73a-1b0b-4461-93cd-0c024738c19e;#5102d73a-1b0b-4461-93cd-0c024733d52d";
string c3 = "|;#5102d73a-1b0b-4461-93cd-0c024738c19e;#SharePointTag|5102d73a-1b0b-4461-93cd-0c024733d52d";
string c4 = "Business pages|;#5102d73a-1b0b-4461-93cd-0c024738cz13;#SharePointTag|5102d73a-1b0b-4461-93cd-0c024733d52d";
string p = @"([a-zA-Z0-9]{8}[-][a-zA-Z0-9]{4}[-][a-zA-Z0-9]{4}[-][a-zA-Z0-9]{4}[-][a-zA-Z0-9]{12})";

MatchCollection mc;

Console.WriteLine("#1");
mc = Regex.Matches(c1, p);
foreach (var id in mc)
    Console.WriteLine(id);

Console.WriteLine("#2");
mc = Regex.Matches(c2, p);
foreach (var id in mc)
    Console.WriteLine(id);

Console.WriteLine("#3");
mc = Regex.Matches(c3, p);
foreach (var id in mc)
    Console.WriteLine(id);

Console.WriteLine("#4");
mc = Regex.Matches(c4, p);
foreach (var id in mc)
    Console.WriteLine(id);

输出:

#1
5102d73a-1b0b-4461-93cd-0c024738c19e
#2
5102d73a-1b0b-4461-93cd-0c024738c19e
5102d73a-1b0b-4461-93cd-0c024733d52d
#3
5102d73a-1b0b-4461-93cd-0c024738c19e
5102d73a-1b0b-4461-93cd-0c024733d52d
#4
5102d73a-1b0b-4461-93cd-0c024738cz13
5102d73a-1b0b-4461-93cd-0c024733d52d
Press any key to continue...
于 2012-05-15T14:52:31.320 回答
4
var possibleGuids = myString.Split("|;#".ToCharArray(), 
                                   StringSplitOptions.RemoveEmptyEntries);
Guid g;
foreach(var poss in possibleGuids)
{
  if(Guid.TryParse(poss, out g))
  {
      // g contains a guid!
  }
}
于 2012-05-15T14:29:20.780 回答
2
string sContent = "your data"; // any of your four forms of input
string sPattern = @"([a-z0-9]*[-]){4}[a-z0-9]*";

MatchCollection mc = Regex.Matches(sContent, sPattern );

foreach (var sGUID in mc)
{
    // Do whatever with sGUID
}
于 2012-05-15T14:28:25.730 回答
1

例如,您可以拆分字符串

 "fist|second".Split('|')

一旦获得 GUID 字符串,您就可以使用

 Guid = new Guid(myString);

对于第一行

var guid = new Guid("Accessibility|5102d73a-1b0b-4461-93cd-0c024738c19e".Split("|")[1]);

对于二线

var myArray = "5102d73a-1b0b-4461-93cd-0c024738c19e;#5102d73a-1b0b-4461-93cd-0c024733d52d".Split(';');
var guid1 = new Guid(myArray[0]);
var guid2 = new Guid(myArray[1].Replace('#',''));

所以你可以这样继续..

于 2012-05-15T14:24:37.730 回答