word是指任何以空格分隔的字符串。
假设文件test.txt有以下由空格分隔的单词：
hello hello hello hell osd
hello
hello
hello
hellojames beroo helloooohellool axnber hello
way
how
我想计算单词hello在每一行中出现的次数。
我使用该命令显示每行awk -F "hello" '{print NF-1}' test.txt中单词hello的出现次数：
3
1
1
1
4
0
0
所以它总共找到 3+1+1+1+4 = 10 次出现。
问题出在第四行：hello作为一个单独的词只出现了 1 次；hellojames和hellooohellool等词不应被计算在内，因为hello不是由空格分隔的。
所以我希望它找到 7 次出现的hello作为单独的单词。
你能帮我写一个返回正确总数 7 次的命令吗？
awk '{ for(i=1; i<=NF; i++) if($i=="hello") c++ } END{ print c }' file.txt
如果您需要它打印每一行：
awk '{ c=1; for(i=0; i<=NF; i++) if($i=="hello") c++; print c }'
grep -o '\<hello\>' filename | wc -l
和位是字边界模式\<，\>因此表达式不会找到foohelloor hellobar。
你也可以使用awk -F '\\<hello\\>' ...来达到同样的效果。
Solution:
sed 's/\s\+/\n/g' test.txt | grep -w hello | wc -l
Explanation:
sed 's/\s\+/\n/g' text.txt
This replaces every span of whitespace with a newline, effectively reformatting the file test.txt so it has one word per line. The command sed 's/FIND/REPLACE/g' replaces the FIND pattern with REPLACE everywhere it appears. The pattern \s\+ means "one or more whitespace characters", and \n is a newline.
grep -w hello
This extracts only those lines that contain hello as a complete word.
wc -l
This counts the number of lines.
If you want to count the number of occurrences per line, you can use the same technique, but process one line at a time:
while read line; do
echo $line | sed 's/\s\+/\n/g' | grep -w hello | wc -l
done < test.txt
cat $FileName | tr '[\040]' '[\012]' | grep $word | wc -l
此命令将更改新行中的空格，然后您可以轻松地 grep 该单词并计算包含给定单词的行数。
a=$(printf "\01")
b=hello
sed -e "s/\<$b\>/ $a /g" -e "s/[^$a]//g" -e "s/$a/ $b /g" file | wc -w
for word in `cat test.txt`; do
if [[ ${word} == hello ]]; then
helloCount=$(( ${helloCount} + 1));
fi;
done;
echo ${helloCount}
只改变“针”和“文件”
#!/usr/bin/env sh
needle="|"
file="file_example.txt"
IFS=$'\n'
counter=0
for line in `cat $file`
do
counter=$[$counter+1]
echo $counter"|"`echo $line | grep -o "$needle" | wc -l`
done
它将打印行号和出现次数，由管道字符分隔