php - 如何回显这个数组的值？

Question

如何单独回显这个数组的值？

Array ( [0] => 20120514 [1] => My Event 3 )

所以

 echo $value[0]; etc

到目前为止我有这个：

foreach (json_decode($json_data_string, true) as $item) {

$eventDate = trim($item['date']);

    // positive limit
    
   $myarray = (explode(',', $eventDate, 2));

foreach ($myarray as $value) {
   echo $value;
}

此回显将整个字符串 no 作为数组输出。如果我这样做？

  echo $value[0};

然后我只得到它的2个字符？？

print_r ：

Array ( [0] => 20120430 [1] => My Event 1 )

Answer 1

foreach ($array as $key => $val) {
   echo $val;
}

Answer 2

这是原始元素数组的简单例程：

for ($i = 0; $i < count($mySimpleArray); $i++)
{
   echo $mySimpleArray[$i] . "\n";
}

Answer 3

为此，您需要在 foreach 循环中设置键和值：

foreach($item AS $key -> $value) {
echo $value;
}

这应该可以解决问题:)

Answer 4

这里的问题在于您的爆炸声明

//$item['date'] presumably = 20120514.  Do a print of this
$eventDate = trim($item['date']);

//This explodes on , but there is no , in $eventDate
//You also have a limit of 2 set in the below explode statement
$myarray = (explode(',', $eventDate, 2));

 //$myarray is currently = to '20'

 foreach ($myarray as $value) {
    //Now you are iterating through a string
    echo $value;
 }

如果您要这样做，请尝试将您的初始 $item['date'] 更改为 2012,04,30 。否则，我不完全确定您要打印什么。

Answer 5

var_dump($value)

它解决了我的问题，希望你也是。