php - 使用 PHP 跨三个 MySQL 表更新/插入

Question

我有 3 张桌子：

1. SMS_IN使用“原始”号码（数据是通过短信发送的，因此所有号码都是短信形式：我正在“分解”它们以将它们变成一个号码）：

   短信文本
   发件人号码
   sent_dt

2. members与会员的手机号码：

   会员ID
   用户名
   comp_id
   电话

3. mobile_numbers_test他们所有的数字表：

   会员ID
   comp_id
   数字
   联系电话
   积极的

我正在尝试通过 2 次检查将SMS_IN（新号码）输入mobile_numbers_test（旧号码）：

1. SMS_IN.sender_number = members.phone; 和
2. 如果SMS_IN.sender_number = mobile_numbers_test.contact_number AND SMS_IN.sms_text（以分解形式）= mobile_numbers_test.numbers，跳过（或覆盖） - 否则INSERT。

这是我到目前为止所拥有的：

include ('database_connection.php');

$result = mysql_query("SELECT phone FROM members")
or die(mysql_error());  
$no=0;
echo'<table>
        <tr>
        <td>Numbers</th>
        <td>From</th>
        <td>Date</th>
        </tr>';
while($row = mysql_fetch_array($result))
    {$no++;
    $phone= $row['phone'];  
    $comp_id =  $row['comp_id'];
    $result1 = mysql_query("SELECT * FROM SMS_IN where sender_number ='$phone'")
    or die(mysql_error()); 
    while($row = mysql_fetch_array($result1))
        {$no++;
        $sms= $row['sms_text'];
        $sms_no=$row['sender_number'];
        $sms_time=$row['sent_dt'];
        $sms_exp = explode("\r\n",$sms);
        foreach($sms_exp as $no )
        { //** not working from here **//

        $result2 = mysql_query("SELECT * FROM members,mobile_numbers_test,SMS_IN 
        where members.phone = SMS_IN.sender_number and 
        mobile_numbers_test.numbers != '$no'
        ")
        or die(mysql_error());

        while($row = mysql_fetch_array($result2))
        {
        $circle=$row['state'];
        $price='Call Us';
        $contact_person=$row['Username'];
        $contact_number=$row['phone'];
        $type='Fancy';
        $per_post='Pre-Paid';
        $provider=$sms_exp[0];
        $date=strtotime($sms_time);
        $ip=$sms_no;
        $old_no=$row['numbers'];;

        if($old_no!=$no){ 
            echo '<tr><td>'.$no.'</td>';
            echo '<td>'.$contact_person.'</td></tr>';
        } else { echo 'Old No';
        }
        }
        }
        }

        }       
    echo'</table>'; 

在这个例子中，我给出echo了答案，以便我知道会发生什么......我该怎么做UPDATE？INSERT

Answer 1

1. 如果不存在，则在on中创建一个UNIQUE索引：mobile_numbers_test(contact_number, numbers)

   ALTER TABLE mobile_numbers_test ADD UNIQUE INDEX (contact_number, numbers);
   

2. 加入你members的SMS_IN加入标准：

   SELECT * FROM members JOIN SMS_IN ON SMS_IN.sender_number = members.phone
   

3. 循环遍历结果集，爆炸数字并插入mobile_numbers_testusing INSERT IGNORE。把它们放在一起（使用 PDO，因为它会让你的生活更轻松，你真的应该停止使用古老的mysql_*函数编写新代码：它们不再被维护并且社区已经开始弃用过程）：

   $dbh = new PDO("mysql:host=$hostname;dbname=$database", $user, $pass);
   
   $select = $dbh->query("
     SELECT * FROM members JOIN SMS_IN ON SMS_IN.sender_number = members.phone
   ") or die($dbh->errorInfo());
   
   $insert = $dbh->prepare("
     INSERT IGNORE INTO mobile_numbers_test
              ( Memberid,  comp_id,  numbers,  contact_number)
       VALUES (:Memberid, :comp_id, :numbers, :contact_number)
   ");
   
   while($sms = $select->fetch()) {
     foreach(explode("\r\n",$sms['sms_text']) as $no) $insert->execute(array(
       'Memberid'       => $sms['Memberid'],
       'comp_id'        => $sms['comp_id'],
       'numbers'        => $no,
       'contact_number' => $sms['sender_number']
     ));
   }