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我正在阅读一本名为《开始安卓游戏》的书。

在书中，它在 SpriteBatcher 类中有以下方法......

public void drawSprite(float x, float y, float width, float height, float angle, TextureRegion region) {
    float halfWidth = width / 2;
    float halfHeight = height / 2;

    float rad = angle * Vector2.TO_RADIANS;
    float cos = FloatMath.cos(rad);
    float sin = FloatMath.sin(rad);

    float x1 = -halfWidth * cos - (-halfHeight) * sin;
    float y1 = -halfWidth * sin + (-halfHeight) * cos;
    float x2 = halfWidth * cos - (-halfHeight) * sin;
    float y2 = halfWidth * sin + (-halfHeight) * cos;
    float x3 = halfWidth * cos - halfHeight * sin;
    float y3 = halfWidth * sin + halfHeight * cos;
    float x4 = -halfWidth * cos - halfHeight * sin;
    float y4 = -halfWidth * sin + halfHeight * cos;

    x1 += x;
    y1 += y;
    x2 += x;
    y2 += y;
    x3 += x;
    y3 += y;
    x4 += x;
    y4 += y;

    verticesBuffer[bufferIndex++] = x1;
    verticesBuffer[bufferIndex++] = y1;
    verticesBuffer[bufferIndex++] = region.u1;
    verticesBuffer[bufferIndex++] = region.v2;

    verticesBuffer[bufferIndex++] = x2;
    verticesBuffer[bufferIndex++] = y2;
    verticesBuffer[bufferIndex++] = region.u2;
    verticesBuffer[bufferIndex++] = region.v2;

    verticesBuffer[bufferIndex++] = x3;
    verticesBuffer[bufferIndex++] = y3;
    verticesBuffer[bufferIndex++] = region.u2;
    verticesBuffer[bufferIndex++] = region.v1;

    verticesBuffer[bufferIndex++] = x4;
    verticesBuffer[bufferIndex++] = y4;
    verticesBuffer[bufferIndex++] = region.u1;
    verticesBuffer[bufferIndex++] = region.v1;

    numSprites++;
}

我的问题是如何平滑地旋转如下图所示的图像，以使图像中的线条看起来不像素化？

我确实有正确尺寸和 DPI 的图像，并且在旋转之前看起来很棒，但是当它旋转时，线条的边缘看起来并不那么好。

在此处输入图像描述

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1 回答 1

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您可以尝试使用 LINEAR 采样而不是 NEAREST，尽管我很难在没有看到问题图片或看到纹理创建代码的情况下猜测更多。

于 2012-05-12T19:14:08.837 回答