4

我有一张这样的桌子：

CREATE TABLE #TEMP (Name VARCHAR(255), START_TIME datetime, END_TIME datetime);

INSERT INTO #TEMP VALUES('John', '2012-01-01 09:00:01', '2012-01-01 12:00:02')
INSERT INTO #TEMP VALUES('John', '2012-01-01 09:40:01', '2012-01-01 11:00:02')
INSERT INTO #TEMP VALUES('John', '2012-01-02 05:00:01', '2012-01-02 05:15:02')
INSERT INTO #TEMP VALUES('David', '2012-01-04 05:00:01', '2012-01-04 05:15:02')
INSERT INTO #TEMP VALUES('David', '2012-01-05 07:01:01', '2012-01-05 15:15:02')

SELECT *
FROM #TEMP

DROP TABLE #TEMP

数据是：

     Name   START_TIME                 END_TIME
1    John   2012-01-01 09:00:01.000    2012-01-01 12:00:02.000
2    John   2012-01-01 09:40:01.000    2012-01-01 11:00:02.000
3    John   2012-01-02 05:00:01.000    2012-01-02 05:15:02.000
4    David  2012-01-04 05:00:01.000    2012-01-04 05:15:02.000
5    David  2012-01-05 07:01:01.000    2012-01-05 08:15:02.000

给定一个数字，比如 6，我试图GROUP BY在这张表上做一个并合并在前后 6 小时的窗口内重叠的时间。因此，在上表中，行1和2将合并为一行，因为它们包含重叠的时间范围：

John 2012-01-01 06:00:01.000 2012-01-01 18:00:02.000

行4和5将被合并，因为减去 6 小时07:01:01.000落入行的窗口4。

在包含大约一百万行的大表上是否有这样做的好方法？

4

1 回答 1

2

我认为最好的方法是创建一个windows表并将 #temp 表与这个新的窗口表连接：

1）步骤1，准备所有可能的窗口间隙的窗口表（包含重叠窗口）：

   SELECT 
      Name,
      dateadd(hour, -6, start_time) as start_w, 
      dateadd(hour, +6, start_time) as end_w
   into #possible_windows
   FROM #TEMP

2）在临时表上创建索引以提高性能

   create index pw_idx on #possible_windows ( Name, start_w)

3) 消除自连接选择中的重叠窗口。这是创建索引的原因：

   select p2.* 
   into #myWindows
   from #possible_windows p1
   right outer join #possible_windows p2
     on p1.name = p2.name and 
        p2.start_w > p1.start_W and p2.start_w <= p1.end_w
   where p1.name is null

4) 使用#myWindows 加入您的表或直接使用它。

在职的：

SELECT 
  Name,
  dateadd(hour, -6, start_time) as start_w, 
  dateadd(hour, +6, start_time) as end_w,
  ROW_NUMBER() over(partition by Name order by Name, 
                    dateadd(hour, -6, start_time) ) as rn
into #possible_windows
FROM #TEMP 

create index pw_idx on #possible_windows ( Name, start_w)

select p2.* 
from #possible_windows p1
right outer join #possible_windows p2
  on p1.name = p2.name and 
     p2.start_w > p1.start_W and p2.start_w <= p1.end_w
where p1.name is null

结果：

Name  start_w       end_w         rn 
----- ------------- ------------- -- 
David 2012-01-03 23:00:012012-01-04 11:00:011  
David 2012-01-05 01:01:012012-01-05 13:01:012  
John  2012-01-01 03:00:012012-01-01 15:00:011  
John  2012-01-01 23:00:012012-01-02 11:00:013

PE：请回去进行性能测试！

于 2012-05-12T14:24:59.183 回答