我想导入一个精灵表并选择一个精灵。我将如何在 Python/pygame 中执行此操作?
问问题
13781 次
4 回答
7
上面的 spritesheet loader 是一个很好的方法。基于该代码,我制作了适用于任何 spritesheet 的通用函数:
#!/usr/bin/python
#
# Sprite Sheet Loader - hammythepig
#
# Edited by Peter Kennedy
#
# License - Attribution - hammythepig
#http://stackoverflow.com/questions/10560446/how-do-you-select-a-sprite-image-from-a-sprite-sheet-in-python
#
# Version = '2.0'
import pygame,sys
from pygame.locals import *
def sprite_sheet(size,file,pos=(0,0)):
#Initial Values
len_sprt_x,len_sprt_y = size #sprite size
sprt_rect_x,sprt_rect_y = pos #where to find first sprite on sheet
sheet = pygame.image.load(file).convert_alpha() #Load the sheet
sheet_rect = sheet.get_rect()
sprites = []
print sheet_rect.height, sheet_rect.width
for i in range(0,sheet_rect.height-len_sprt_y,size[1]):#rows
print "row"
for i in range(0,sheet_rect.width-len_sprt_x,size[0]):#columns
print "column"
sheet.set_clip(pygame.Rect(sprt_rect_x, sprt_rect_y, len_sprt_x, len_sprt_y)) #find sprite you want
sprite = sheet.subsurface(sheet.get_clip()) #grab the sprite you want
sprites.append(sprite)
sprt_rect_x += len_sprt_x
sprt_rect_y += len_sprt_y
sprt_rect_x = 0
print sprites
return sprites
#VERSION HISTORY
#1.1 - turned code into useable function
#2.0 - fully functional sprite sheet loader
作为参考,这会将工作表从左到右一次一排地切割成单独的精灵。
于 2012-06-10T19:50:42.740 回答
6
我做了这个,你可能会感兴趣:
import pygame, sys
from pygame.locals import *
SCREEN_X=400
SCREEN_Y=400
#Screen size
SPRT_RECT_X=0
SPRT_RECT_Y=0
#This is where the sprite is found on the sheet
LEN_SPRT_X=100
LEN_SPRT_Y=100
#This is the length of the sprite
screen = pygame.display.set_mode((SCREEN_X, SCREEN_Y)) #Create the screen
sheet = pygame.image.load('C:\YOURFILE') #Load the sheet
sheet.set_clip(pygame.Rect(SPRT_RECT_X, SPRT_RECT_Y, LEN_SPRT_X, LEN_SPRT_Y)) #Locate the sprite you want
draw_me = sheet.subsurface(sheet.get_clip()) #Extract the sprite you want
backdrop = pygame.Rect(0, 0, SCREEN_X, SCREEN_Y) #Create the whole screen so you can draw on it
screen.blit(draw_me,backdrop) #'Blit' on the backdrop
pygame.display.flip()
#Draw the sprite on the screen
希望我能帮上忙
于 2012-05-15T18:49:19.567 回答
0
aquasheep 发布的上述代码非常棒!虽然在行:
for i in range(0,sheet_rect.height-len_sprt_y,size[1]):#rows
for i in range(0,sheet_rect.width-len_sprt_x,size[0]):#columns
我不得不删除它-len_sprt_y
,-len_sprt_x
它只是不会加载 x 和 y 轴上的最后一个精灵。它可能会根据精灵表 x、y 大小和实际精灵大小而有所不同。
于 2015-10-19T20:09:00.033 回答
0
你不需要打电话set_clip
,get_clip
正如其他答案中提到的那样。只需将一个矩形、元组或列表传递给Surface.subsurface
.
# The size of a sprite in this example is 64x64 pixels.
x_coord = 64 * 2 # This would be the third column.
y_coord = 64 * 3 # Fourth row.
width = 64
height = 64
sheet = pygame.image.load('your_sprite_sheet.png').convert_alpha()
single_image = sheet.subsurface((x_coord, y_coord, width, height))
于 2017-06-29T10:20:34.700 回答