我有两个时间值，如下所示
$time = 06:58:00;
$time2 = 00:40:00;
我这样做是为了计算特定用户的约会和可用时间，所以我尝试了这种方式
$max_date=abs(strtotime($time) + strtotime($time2));
但它返回 $max_date =2673452280 任何建议请
问问题
29246 次
7 回答
40
此代码示例将花费一小时$time并将小时添加$time2到其中
例如：时间=06:58:00，时间2=00:40:00，结果=07:38:00
$time = "06:58:00";
$time2 = "00:40:00";
$secs = strtotime($time2)-strtotime("00:00:00");
$result = date("H:i:s",strtotime($time)+$secs);
于 2012-05-11T19:05:23.590 回答
9
使用这个功能...
function sum_the_time($time1, $time2) {
$times = array($time1, $time2);
$seconds = 0;
foreach ($times as $time)
{
list($hour,$minute,$second) = explode(':', $time);
$seconds += $hour*3600;
$seconds += $minute*60;
$seconds += $second;
}
$hours = floor($seconds/3600);
$seconds -= $hours*3600;
$minutes = floor($seconds/60);
$seconds -= $minutes*60;
if($seconds < 9)
{
$seconds = "0".$seconds;
}
if($minutes < 9)
{
$minutes = "0".$minutes;
}
if($hours < 9)
{
$hours = "0".$hours;
}
return "{$hours}:{$minutes}:{$seconds}";
}
于 2013-07-17T08:09:38.677 回答
1
strtotime 函数以完整日期为参数，有效格式如下： http ://www.php.net/manual/en/datetime.formats.php
您可以在http://php.net/manual/en/function.strtotime.php的函数的在线 PHP 手册中看到这一点
于 2012-05-11T19:00:21.373 回答
1
如果您之前从数据库构建这些时间字符串，您可能希望将它们重建为如下所示：
$time = "00:06:58";
$time2 = "40 minutes";
$timestamp = strtotime($time." +".$time2);
$endTime = date("d.m.Y H:i:s", $timestamp);
于 2012-05-11T19:05:03.803 回答
1
使用 php 添加两次的最简单方法是：
1) 将时间从 H:i:s (例如 08:15:40) 格式转换为秒。
2) 对第二次时间值 ref:step 1 执行相同操作
3) 添加转换后的值并将其存储为 php 变量
4) 现在将总计（以秒为单位）转换为 H:i:s
并且它适用于我。
PHP 脚本：
$str_time ="08:04:40";
$str_time = preg_replace("/^([\d]{1,2})\:([\d]{2})$/", "00:$1:$2", $str_time);
sscanf($str_time, "%d:%d:%d", $hours, $minutes, $seconds);
$hrs_old_seconds = $hours * 3600 + $minutes * 60 + $seconds;
$str_time ="02:10:22";
$str_time = preg_replace("/^([\d]{1,2})\:([\d]{2})$/", "00:$1:$2", $str_time);
sscanf($str_time, "%d:%d:%d", $hours, $minutes, $seconds);
$hrs_toadd_seconds = $hours * 3600 + $minutes * 60 + $seconds;
$hrs_old_int1 = $hrs_old_seconds + $hrs_toadd_seconds;
echo $Total=gmdate("H:i:s", $hrs_old_int1);
结果=：10:15:02
于 2016-06-18T05:08:00.933 回答
1
Anudeep 的解决方案非常适合我的用例，但我还需要能够添加负时间。这是他的代码的略微编辑版本，用于获取和返回负时间字符串（例如“-01:01:01”）：
public static function sum_the_times($time1, $time2)
{
$times = array($time1, $time2);
$seconds = 0;
$negative = false;
foreach ($times as $time) {
list($hour,$minute,$second) = explode(':', $time);
if(substr($hour,0,1) == '-'){
$seconds -= substr($hour,1)*3600;
$seconds -= $minute*60;
$seconds -= $second;
} else {
$seconds += $hour*3600;
$seconds += $minute*60;
$seconds += $second;
}
}
if (substr($seconds, 0, 1) == '-') {
$negative = true;
$seconds = ($seconds * -1);
}
$hours = floor($seconds/3600);
$seconds -= $hours*3600;
$minutes = floor($seconds/60);
$seconds -= $minutes*60;
if ($seconds < 9) {
$seconds = "0".$seconds;
}
if ($minutes < 9) {
$minutes = "0".$minutes;
}
if ($hours < 9) {
$hours = "0".$hours;
}
return ($negative ? "-" : "")."{$hours}:{$minutes}:{$seconds}";
}
于 2019-03-06T00:58:21.327 回答
0
你可以试试这个
$time = "04:00:00";
$time2 = "03:30:00";
$result = date("H:i:s",strtotime($time)+strtotime($time2));
echo $result;
它提供输出 07:30:00 但有时在不同版本的操作系统中不起作用。如果您想获得时间总和，则可以使用此代码
<?php
function CalculateTime($time1, $time2) {
$time1 = date('H:i:s',strtotime($time1));
$time2 = date('H:i:s',strtotime($time2));
$times = array($time1, $time2);
$seconds = 0;
foreach ($times as $time)
{
list($hour,$minute,$second) = explode(':', $time);
$seconds += $hour*3600;
$seconds += $minute*60;
$seconds += $second;
}
$hours = floor($seconds/3600);
$seconds -= $hours*3600;
$minutes = floor($seconds/60);
$seconds -= $minutes*60;
if($seconds < 9)
{
$seconds = "0".$seconds;
}
if($minutes < 9)
{
$minutes = "0".$minutes;
}
if($hours < 9)
{
$hours = "0".$hours;
}
return "{$hours}:{$minutes}:{$seconds}";
}
$time1= '23:32:05';
$time2 = '01:29';
echo CalculateTime($time1,$time2);
?>
在第二个代码中，您可以以小时：分钟或小时：分钟：秒发送时间。此代码接受这两种格式，因为它会自动转换时间
于 2019-06-07T04:27:59.257 回答