输入是：
+--------+-------+----------+----------+
| RESULT | EXMID | EXSUBJID | SID |
+--------+-------+----------+----------+
| 11 | 4 | 6 | Student4 |
| 12 | 4 | 6 | Student3 |
| 25 | 4 | 6 | Student5 |
| 45 | 4 | 10 | Student8 |
| 12 | 4 | 10 | Student4 |
| 100 | 4 | 10 | Student5 |
| 12 | 4 | 10 | Student3 |
+--------+-------+----------+----------+
我有这张表，其中列出了在不同科目的特定考试中出现的学生名单。
总科目是考试的科目总数。Pass 代表学生在任何科目中通过的状态，fail 代表学生在任何科目中失败的状态。
现在的问题是考试中通过、失败和通过百分比的总计数。如果学生在任何科目中不及格，他/她就是不及格。
我尝试了很多东西，但无法得到结果。
这就是我得到的：
+----------+------------+------+------+--------------+
| STUDENT | TOTAL_SUBJ | PASS | FAIL | PASS_PERCENT |
+----------+------------+------+------+--------------+
| Student3 | 2 | 1 | 1 | 50.00 |
| Student4 | 2 | 0 | 2 | 0.00 |
| Student5 | 2 | 2 | 0 | 100.00 |
| Student8 | 2 | 1 | 0 | 100.00 |
+----------+------------+------+------+--------------+
任何人都可以为它提供一个好的解决方案吗？
这是我对上述输出的查询。
SELECT DISTINCT exreslt.SID AS STUDENT,
COUNT(exsubj.EXSUBJID) AS TOTAL_SUBJ,
SUM(exreslt.RESULT >= exsubj.PASS) AS PASS,
SUM(exreslt.RESULT < exsubj.PASS) AS FAIL,
ROUND(SUM(exreslt.RESULT >= exsubj.PASS)*100/ COUNT(exreslt.SID),2) AS 'PASS_PERCENT'
FROM EXAMSUBJ AS exsubj
STRAIGHT_JOIN EXAMRESULT AS exreslt
WHERE exsubj.EXSUBJID = exreslt.EXSUBJID AND exsubj.EXMID = exreslt.EXMID AND exsubj.EXMID=4 GROUP BY exreslt.SID ;
我希望输出是
+----------+------------+------+------+--------------+
| STUDENT | TOTAL_SUBJ | PASS | FAIL | PASS_PERCENT |
+----------+------------+------+------+--------------+
| 4 | 2 | 2 | 2 | 50.00 |
+----------+------------+------+------+--------------+
如果任何学生在任何一门科目中不及格，他将被视为不及格，否则他将通过。