php - php上次登录时间和当前登录时间差...对还是错？

Question

我的代码在那里：

如何显示上次登录时间（年、月、周、日、时间、秒）.. 我试过但输出错误

上次登录时间：2012-05-11 10:16:51 当前时间：2012-05-11 10:35:51

$diff_seconds = strtotime($current_time) - strtotime($lastLoginTime); 

这是正确的$diff_seconds -1336724211

Answer 1

The following code gives me 1140:

<?php echo strtotime('2012-05-11 10:35:51') - strtotime('2012-05-11 10:16:51');  ?>

There probably is an error elsewhere in your code that you're not showing us.

Answer 2

我无法重现那个。我做了

$time1 = '2012-05-11 10:16:51';
$time2 = '2012-05-11 10:35:51';

echo strtotime($time1) - strtotime($time2);
echo '<br>';
echo strtotime($time2) - strtotime($time1);

我得到了

-1140

1140

看起来合法。请出示您的代码。也许你没有字符串，它用你的年份数字做了一些奇怪的计算？

Answer 3

您想试试date_diff (PHP 5 >= 5.3.0) 作为选项吗？

http://php.net/manual/en/datetime.diff.php

<?php
$datetime1 = date_create('2012-05-11 10:16:51');
$datetime2 = date_create('2012-05-11 10:35:51');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%s seconds');
?>