1

我有桌子：

事件

    -----+--------------------------------+
    | 编号 | 事件名称 |
    -----+--------------------------------+
    | 1 | 保龄球 |
    | 2 | 测验 |
    | 3 | 飞镖 |
    | 4 | 游泳池 |
    | 5 | 寻宝 |
    | 6 | 斯诺克 |
    -----+--------------------------------+

竞争对手

    ------+------------------+
    | 编号 | 竞争对手姓名 |
    ------+------------------+
    | 1 | 微软 |
    | 2 | 英国广播公司 |
    | 3 | 脸书 |
    ------+------------------+

结果

    ------+----------------+---------+--------------+
    | 编号 | 竞争对手ID | 事件ID | 事件评分 |
    ------+----------------+---------+--------------+
    | 1 | 1 | 1 | 12 |
    | 2 | 1 | 2 | 11 |
    | 3 | 1 | 3 | 23 |
    | 4 | 2 | 1 | 66 |
    | 5 | 2 | 2 | 12 |
    | 6 | 2 | 3 | 11 |
    | 7 | 2 | 4 | 23 |
    | 8 | 2 | 5 | 66 |
    | 3 | 2 | 6 | 23 |
    | 4 | 3 | 1 | 66 |
    | 5 | 3 | 2 | 12 |
    | 6 | 3 | 3 | 11 |
    | 7 | 3 | 4 | 23 |
    | 8 | 3 | 6 | 66 |
    ------+----------------+---------+--------------+

我想从中获得这样的输出：

    --------------+---------+---------+--------+------ +--------------+----------
    | 竞争对手 | 保龄球 | 测验 | 飞镖 |游泳池 |寻宝 | 斯诺克 |
    --------------+---------+---------+--------+------ +--------------+----------
    | 微软 | 12 | 11 | 23 | 0 | 0 | 0 |
    | 英国广播公司 | 66 | 12 | 11 | 23 | 66 | 23 |
    | 脸书 | 66 | 12 | 11 | 23 | 0 | 66 |
    --------------+---------+---------+--------+------ +--------------+----------

我已经尝试了各种连接和嵌套 php，但我就是无法破解它。我什至不确定这是否可能。我的 SQL 知识不是很好，我尝试了一些教程，但它们没有涵盖这种查询。

4

5 回答 5

2 
SELECT   competitors.competitorName                          AS competitor,
         SUM(IF(results.eventId = 1, results.eventScore, 0)) AS Bowling,
         SUM(IF(results.eventId = 2, results.eventScore, 0)) AS Quiz,
         -- etc.
FROM     competitors
  LEFT JOIN results ON results.competitorId = competitors.id
GROUP BY competitors.id
于 2012-05-11T09:49:40.880 回答
1

此请求通常可以，但每次在表事件中添加新条目时都需要进行修改。

SELECT
    comp.competitorName as competitor,
    rbowling.eventScore as Bowling,
    rquiz.eventScore as Quiz,
    rdarts.eventScore as Darts,
    rpool.eventScore as Pool,
    rtreasure.eventScore as Treasure_Hunt,
    rsnooker.eventScore as Snooker
FROM competitors comp
LEFT JOIN result rbowling ON (rbowling.eventId = 1 AND comp.id = rbowling.competitorId)
LEFT JOIN result rquiz ON (rquiz.eventId = 2 AND comp.id = rquiz.competitorId)
LEFT JOIN result rdarts ON (rdarts.eventId = 3 AND comp.id = rdarts.competitorId)
LEFT JOIN result rpool ON (rpool.eventId = 4 AND comp.id = rpool.competitorId)
LEFT JOIN result rtreasure ON (rtreasure.eventId = 5 AND comp.id = rtreasure.competitorId)
LEFT JOIN result rsnooker ON (rsnooker.eventId = 6 AND comp.id = rsnooker.competitorId)
GROUP BY comp.id;
于 2012-05-11T09:56:49.657 回答
0

您基本上是在寻找数据透视表。有一个例子和here。

于 2012-05-11T09:45:02.110 回答
0

您可以像这样通过 php 创建查询

<?php
$events = array('Assume this is array of events table with id,eventName as key');

$column = array();
foreach($events as $event)
{
     $column[] = 'SUM(IF(results.eventId = '.$event['id'].', results.eventScore, 0)) AS '.$event['eventName'];
}

$sql = 'SELECT   competitors.competitorName AS competitor,';
$sql .= implode(',',$column);
$sql .= ' FROM competitors';
$sql .= ' LEFT JOIN results ON results.competitorId = competitors.id';
$sql .= ' GROUP BY competitors.id';
//Put $sql into mysql_query then

然后，动态获取行

while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
    foreach($row as $k=>$v) 
    {
         //Here you get Column Name as $k  and data value as $v
    }
}
于 2012-05-11T10:03:03.270 回答
0

您正在寻找的查询是这个：

SELECT r.eventScore, e.eventName, c.competitorName
FROM results r
LEFT JOIN events e ON e.id = r.eventId
LEFT JOIN competitors c ON c.id = r.competitorId

通过此查询，您将获得每个结果的基础事件和竞争对手名称。然后你必须在 PHP 中管理数据来创建你想要的表......但我想这将很难实现......

我最好分别对竞争对手和事件进行选择，然后获取所有得分结果并创建如下表格：

// we have $competitors array containing id => name
// we have $events array containing id => name
// we have $results array containing competitorId => [ eventId => score ]
echo '<table>';
echo '<tr><td>Competitors</td>';
foreach($events as $e)
    echo '<td>'.$e.'</td>';
echo '</tr>';
foreach($results as $cId => $val) {
    echo '<tr><td>'.$competitors[$cId].'</td>';
    foreach($events as $eId => $name) {
        echo '<td>'.$val[$eId].'</td>';
    }
    echo '</tr>';
}
echo '</table>';

但这只是一个快速且不是很好的解决方案，我最好采用一个查询的方式。

于 2012-05-11T10:00:39.623 回答