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有没有办法将一个应用程序扩展到另一个 mdi 应用程序?例如。我有 3 个应用程序:“Transaction”、“SalesOrder”和“PurchaseOrder”我想通过在“SalesOrder”和“PurchaseOrder”中扩展它来重用“Transaction”。干净的方法是什么?

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2 回答 2

1

您可以简单地定义一个application具有特定名称的名称,然后extend从中定义。

BaseApp.js

Ext.application({
    name: 'BaseApp',
    launch: function () {
        alert("Base App Launch");
    }
});

ChildApp.js

Ext.application({
    //extend from base app
    extend: 'BaseApp',
    name: 'ChildApp',
    launch: function () {
        alert("Child App Launch");
    }
});
于 2012-11-11T11:22:24.680 回答
0

是的,从 ExtJS 4.2 开始就有可能。

在http://docs.sencha.com/extjs/4.2.2/#!/api/Ext.app.Application检查文档部分“从 Ext.app.Application 派生”

这是一个小例子:

Ext.define('Transaction.Application', {
    extend: 'Ext.app.Application',
    requires: [],

    // application namespace
    name: 'Transaction',

    // name of the app instance in DOM (e.g. Transaction.instance)
    //appProperty: 'instance',

    // application folder
    appFolder: '/js/Transaction',

    autoCreateViewport: true,

    controllers: [
    ],

    views: [
    ],

    launch: function() {
        console.log('application started');
    }
});

Ext.define('SalesOrder.Application', {
    extend: 'Transaction.Application',
    requires: [],

    // application namespace
    name: 'SalesOrder',

    // application folder
    appFolder: '/js/SalesOrder',

    autoCreateViewport: false,

    controllers: [
    ],

    views: [
    ],

    launch: function() {
        Ext.create('Ext.container.Viewport');
        this.callParent();
    }
});

Ext.define('PurchaseOrder.Application', {
    extend: 'Transaction.Application',
    requires: [],

    // application namespace
    name: 'PurchaseOrder',

    // application folder
    appFolder: '/js/PurchaseOrder',

    autoCreateViewport: false,

    controllers: [
    ],

    views: [
    ],

    launch: function() {
        Ext.create('Ext.container.Viewport');
        this.callParent();
    }
});

Ext.application('PurchaseOrder.Application');

// Then you can acces your application instance anywhere:
var app = PurchaseOrder.getApplication();
于 2013-10-13T08:23:32.807 回答