1

我试图在不知道键名的情况下从 json 响应中打印所有“键、值”（例如，不使用语法 json['example']）。我正在使用使用 iteritems() 的递归函数来执行此操作，但我遇到了一些问题：

这是我试图阅读的 Json 响应：

{"servers": [{"id": "a059eccb-d929-43b2-8db3-b32b6201d60f", "links": [{"href": "http://192.168.100.142:8774/v2/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "self"}, {"href": "http://192.168.100.142:8774/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "bookmark"}], "name": "birk"}]}

这是我正在使用的功能：

def format_main_response(self, json_string):
    print "json:       " + json_string
    content = json.loads(str(json_string))
    for key, value in content.iteritems():
        print key
        if type(value) == type(['']):
            strg = str(json.dumps(value))
            strg = strg.strip('[]')
            self.format_main_response(strg)
        else:
            print value

我正在使用 strip 函数从我的 json 字符串中取出所有的 '[ ]' 。如果我没有这样做，我在尝试使用 'json.loads()' 函数加载它时会出错。

 Traceback (most recent call last):
      File "main.py", line 135, in <module>
        formatter.format_main_response(nova_API.list_servers())
      File "/home/python/jsonformatter.py", line 51, in format_main_response
        self.format_main_response(strg, mod)
      File "/home/python/jsonformatter.py", line 51, in format_main_response
        self.format_main_response(strg, mod)
      File "/home/python/jsonformatter.py", line 31, in format_main_response
        for key, value in content.iteritems():
    AttributeError: 'list' object has no attribute 'iteritems'

我的问题是，在某些时候应该打印的 json 看起来像这样，没有'[]'：

{"href": "http://192.168.100.142:8774/v2/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "self"}, {"href": "http://192.168.100.142:8774/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "bookmark"}

当函数试图从这个 json 中找到“键、值”时，我收到了这个错误： 

 Traceback (most recent call last): File "main.py", line 135, in <module>
    formatter.format_main_response(nova_API.list_servers())
  File "/home/python/jsonformatter.py", line 34, in format_main_response
    self.format_main_response(strg)
  File "/home/python/jsonformatter.py", line 34, in format_main_response
    self.format_main_response(strg)
  File "/home/python/jsonformatter.py", line 28, in format_main_response
    content = json.loads(str(json_string))
  File "/usr/lib/python2.7/json/__init__.py", line 326, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python2.7/json/decoder.py", line 369, in decode
    raise ValueError(errmsg("Extra data", s, end, len(s)))
ValueError: Extra data: line 1 column 135 - line 1 column 273 (char 135 - 273)

在这种情况下我该怎么办？或者任何其他方式来获得相同的结果？

4

3 回答 3

2

使用它：

def format_main_response(json_string):
    print "json:       " + json_string
    content = json.loads(str(json_string))
    for key, value in content.iteritems():
        print key
        if type(value) == type(['']):
            for sub_value in value:
                strg = str(json.dumps(sub_value))
                format_main_response(strg)
        else:
            print value

结果是这样的：

~$ python test_pdb.py 
json:       {"servers": [{"id": "a059eccb-d929-43b2-8db3-b32b6201d60f", "links": [{"href": "http://192.168.100.142:8774/v2/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "self"}, {"href": "http://192.168.100.142:8774/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "bookmark"}], "name": "birk"}]}
servers
json:       {"id": "a059eccb-d929-43b2-8db3-b32b6201d60f", "links": [{"href": "http://192.168.100.142:8774/v2/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "self"}, {"href": "http://192.168.100.142:8774/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "bookmark"}], "name": "birk"}
id
a059eccb-d929-43b2-8db3-b32b6201d60f
links
json:       {"href": "http://192.168.100.142:8774/v2/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "self"}
href
http://192.168.100.142:8774/v2/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f
rel
self
json:       {"href": "http://192.168.100.142:8774/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "bookmark"}
href
http://192.168.100.142:8774/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f
rel
bookmark
name
birk
于 2012-05-10T19:26:24.237 回答
2

怎么样：

jsonStr = {"href": "http://192.168.100.142:8774/v2/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "self"}, {"href": "http://192.168.100.142:8774/2ad1fc162c254e59bea043560b7f73cb/servers/a059eccb-d929-43b2-8db3-b32b6201d60f", "rel": "bookmark"}
print json.dumps(jsonStr, sort_keys=True, indent=2, separators=(',', ': '))

这应该给你你想要的格式

于 2013-03-07T20:14:34.023 回答
0

下面的代码递归遍历 json 响应并打印键值对：技巧是在 main 中只加载一次 json 响应，然后递归遍历响应：

def parse_json_response(content):

    if len (content.keys()) > 1 :
        for key, value in content.iteritems():
           print "key : ", key
           print "Value", value

            if type(value) is dict:
                parse_json_response(value)
    else:
        print value

if __name__ == '__main__':

    content = json.loads(str(response))
    parse_json_response(content)

希望能帮助到你。

于 2015-07-10T12:11:58.790 回答