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好的，我被困在这一点上......我想比较两个文件并将字符串从一个文件复制（替换）到另一个文件。

示例文件 1：

01cd74a8h: 65 00 00 00 54 45 53 54 00 00 00 00 00 00 00 00 ; e...TEST........
01cd74b8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd74c8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd74d8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd74e8h: 00 00 00 00 00 00 20 C5 00 00 00 00 00 00 20 C5 ; ...... ?..... ?
01cd74f8h: 00 00 20 45 00 00 00 00 00 00 20 45 01 00 00 00 ; .. E...... E....
01cd7508h: 00 00 00 00 00 00 00 00 C9 00 00 00 54 61 6D 20 ; ........?..Tam 
01cd7518h: 54 61 20 51 75 61 6E 00 00 00 00 00 00 00 00 00 ; Ta Quan.........
01cd7528h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd7538h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd7548h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 20 45 ; .............. E
01cd7558h: 00 00 00 00 00 00 20 C5 00 00 F0 45 00 00 00 00 ; ...... ?.餎....
01cd7568h: 00 00 20 45 01 00 00 00 00 00 00 00 00 00 00 00 ; .. E............
01cd7578h: 2D 01 00 00 4C 69 65 75 20 43 68 69 6E 68 20 51 ; -...Lieu Chinh Q
01cd7588h: 75 61 6E 00 00 00 00 00 00 00 00 00 00 00 00 00 ; uan.............
01cd7598h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd75a8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd75b8h: 00 00 00 00 00 00 F0 C5 00 00 00 00 00 00 20 C5 ; ......鹋...... ?
01cd75c8h: 00 00 20 C5 00 00 00 00 00 00 20 45 01 00 00 00 ; .. ?..... E....
01cd75d8h: 00 00 00 00 00 00 00 00 91 01 00 00 56 6F 20 54 ; ........?..Vo T
01cd75e8h: 68 69 65 6E 20 43 61 63 20 31 00 00 00 00 00 00 ; hien Cac 1......
01cd75f8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd7608h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01cd7618h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 48 C4 ; ..............H?
01cd7628h: 00 00 00 00 00 00 48 C4 00 00 48 44 00 00 00 00 ; ......H?.HD....
01cd7638h: 00 00 48 44 00 00 00 00 10 CA 9A 3B 00 00 00 00 ; ..HD.....蕷;....

示例文件 2：

01b954a8h: 65 00 00 00 43 65 6E 74 72 61 6C 20 56 61 6C 6C ; e...Central Vall
01b954b8h: 65 79 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ey..............
01b954c8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01b954d8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01b954e8h: 00 00 00 00 00 00 20 C5 00 00 00 00 00 00 20 C5 ; ...... ?..... ?
01b954f8h: 00 00 20 45 00 00 00 00 00 00 20 45 01 00 00 00 ; .. E...... E....
01b95508h: 00 00 00 00 00 00 00 00 C9 00 00 00 48 69 6C 6C ; ........?..Hill
01b95518h: 20 56 61 6C 6C 65 79 00 00 00 00 00 00 00 00 00 ;  Valley.........
01b95528h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01b95538h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01b95548h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 20 45 ; .............. E
01b95558h: 00 00 00 00 00 00 20 C5 00 00 F0 45 00 00 00 00 ; ...... ?.餎....
01b95568h: 00 00 20 45 01 00 00 00 00 00 00 00 00 00 00 00 ; .. E............
01b95578h: 2D 01 00 00 52 69 76 65 72 73 69 64 65 20 50 6C ; -...Riverside Pl
01b95588h: 61 69 6E 73 00 00 00 00 00 00 00 00 00 00 00 00 ; ains............
01b95598h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01b955a8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01b955b8h: 00 00 00 00 00 00 F0 C5 00 00 00 00 00 00 20 C5 ; ......鹋...... ?
01b955c8h: 00 00 20 C5 00 00 00 00 00 00 20 45 01 00 00 00 ; .. ?..... E....
01b955d8h: 00 00 00 00 00 00 00 00 91 01 00 00 46 6F 72 62 ; ........?..Forb
01b955e8h: 69 64 64 65 6E 20 54 6F 77 65 72 20 31 46 00 00 ; idden Tower 1F..
01b955f8h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01b95608h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ................
01b95618h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 48 C4 ; ..............H?
01b95628h: 00 00 00 00 00 00 48 C4 00 00 48 44 00 00 00 00 ; ......H?.HD....
01b95638h: 00 00 48 44 00 00 00 00 10 CA 9A 3B 00 00 00 00 ; ..HD.....蕷;....

我想要做的是将 File1 与 File2 进行比较，以查看项目 ID 中是否有任何匹配项，并将 File2 的信息复制到 File1，仅当项目存在时。

项目 ID 在项目名称后面 4 个字节开始。

  01b954a8h: 65 00 00 00 43 65 6E 74 72 61 6C 20 56 61 6C 6C ; e...Central Vall
  01b954b8h: 65 79 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ; ey..............

  01b95508h: 00 00 00 00 00 00 00 00 C9 00 00 00 48 69 6C 6C ; ........?..Hill
  01b95518h: 20 56 61 6C 6C 65 79 00 00 00 00 00 00 00 00 00 ;  Valley.........

在这里你可以看到“65 00”和“C9 00”分别是Central Valley和Hill Valley的ID。

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2 回答 2

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对我来说，不清楚为什么要在 Hex 中执行此操作。似乎您可以将其作为文本处理。

我的想法是，您应该考虑使用正则表达式来查找以空格分隔的单词并备份几个字符以获取 ID 字符（如果需要，可以将其转换为十六进制）。

于 2012-05-10T18:46:56.680 回答
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不是将项目加载到列表框中，而是将项目加载到两个 Dictionary 对象中（其中整数是项目的 ID，字符串是项目的描述。每个文件加载一个字典。然后比较字典中的项目，做任何事情您需要对一本字典进行修改，然后将其保存回文件中。

于 2012-05-10T18:49:23.523 回答