cyclomatic-complexity - 控制流图和圈复杂度

Question

我必须找到这段代码的控制流图和圈复杂度，然后提出一些白盒测试用例和黑盒测试用例。但是我在为代码制作 CFG 时遇到了麻烦。

也希望对测试用例有一些帮助。

private void downShift(int index)
{
    // index of "child", which will be either index * 2 or index * 2 + 1
    int childIndex;

    // temp storage for item at index where shifting begins
    Comparable temp = theItems[index];

    // shift items, as needed
    while (index * 2 <= theSize)
    {
        // set childIndex to "left" child
        childIndex = index * 2;

        // move to "right" child if "right" child < "left" child
        if (childIndex != theSize && theItems[childIndex + 1].compareTo(theItems[childIndex]) < 0)
            childIndex++;

        if (theItems[childIndex].compareTo(temp) < 0)
        {
        // shift "child" down if child < temp
            theItems[index] = theItems[childIndex];
        }
        else
        {
            // shifting complete
            break;
        }

        // increment index
        index = childIndex;
    }

    // position item that was originally at index where shifting began
    theItems[index] = temp;
}

Answer 1

这里的基本圈复杂度是4：while + if + if + 1。如果你考虑像Understand或CMTJava所做的扩展圈复杂度，你还需要为合取加1，所以它是5。无条件控制语句如因为break不影响圈复杂度值。