我应该如何获取默认网关的 IP 地址?而不是从 /proc 读取条目,是否有任何独立的 API 可用?
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5943 次
2 回答
5
您可以使用libnl这是一个通过 NETLINK 套接字与内核通信的库。
获取默认路由的一个简单示例是(请添加错误检查和所需的标头)
void cb_route (struct nl_object *cb, void *arg) {
struct rtnl_route *route = (struct rtnl_route*) cb;
/* do what you need to do with rtnl_route object
* e.g. copy it to arg, etc.
*/
struct nl_addr *tmp_addr;
tmp_addr = rtnl_route_get_gateway(route);
len = nl_addr_get_len(tmp_addr);
memcpy(arg, nl_addr_get_binary_addr(tmp_addr), len);
}
int get_route () {
struct nl_handle *nlh;
struct nl_cache *route_cache;
struct rtnl_route *filter;
struct nl_addr *dst;
char *gw = malloc(16); //enough room for IPv6 if needed
char n = '0';
nlh = nl_handle_alloc();
if (!nlh)
return -1;
nl_connect(nlh, NETLINK_ROUTE);
route_cache = rtnl_route_alloc_cache();
if (nl_cache_is_empty(route_cache))
return 0;
dst = nl_addr_build(AF_INET, &n, 0);
filter = rtnl_route_alloc();
rtnl_route_set_scope(filter, RT_SCOPE_UNIVERSE);
rtnl_route_set_family(filter, AF_INET);
rtnl_route_set_table(filter, RT_TABLE_MAIN);
rtnl_route_set_dst(filter, dst);
nl_cache_foreach_filter(route_cache, (struct nl_object*) filter, cb_filter_route, gw);
/* gw should now contain the binary representation of the default gw. use inet_ntop to convert it */
return 0;
}
于 2012-05-09T10:38:56.197 回答
0
一个技巧是使用套接字 api 尝试连接到无法访问的 ip。“无法到达的目的地”的响应将来自您的默认网关。
于 2012-05-09T12:31:05.183 回答