excel - 如何在不在 VBA 中硬编码其名称的情况下引用 Excel 工作表？

Question

我正在为 excel 创建一个宏，用于将一个 excel 表复制到另一个 excel 表。

这是有效的：

Function CopyFile()

   Dim Wb1 As Workbook
   Dim Wb2 As Workbook
   Dim ws1 As Worksheet
   Dim ws2 As Worksheet

   Set Wb1 = ActiveWorkbook   
   Set ws1 = Wb1.Worksheets("Task")
   Set Wb2 = Workbooks.Open("D:\Outlook\dest.xlsx")

   ws1.Copy Wb2.Worksheets(1)

   Wb2.Save
   Wb2.Close
   Wb1.Activate   

End Function

但我不想使用硬编码字符串来获取工作表名称 Set ws1 = Wb1.Worksheets("Task")。而是想使用函数参数。

以下代码不起作用：

Function CopyFile(name As String)

   Dim Wb1 As Workbook
   Dim Wb2 As Workbook
   Dim ws1 As Worksheet
   Dim ws2 As Worksheet

   Set Wb1 = ActiveWorkbook

   Set ws1 = Wb1.Worksheets(name)
   Set Wb2 = Workbooks.Open("D:\Outlook\dest.xlsx")
   ws1.Copy Wb2.Worksheets(1)

   Wb2.Save
   Wb2.Close
   Wb1.Activate

End Function

Answer 1

这个对我有用。如果你传递一个不存在的名字，你会得到一个错误。也许

Function CopyFile(sSheetName As String)

    Dim wbSource As Workbook
    Dim wbDest As Workbook
    Dim wsSource As Worksheet
    Dim wsDest As Worksheet

    Set wbSource = ActiveWorkbook

    On Error Resume Next
        Set wsSource = wbSource.Worksheets(sSheetName)
    On Error GoTo 0

    If Not wsSource Is Nothing Then
        Set wbDest = Workbooks.Open("D:\Outlook\dest.xlsx")
        wsSource.Copy wbDest.Worksheets(1)

        wbDest.Save
        wbDest.Close
        wbSource.Activate
    End If

End Function

作品“名称”是 VBA 中的保留字。您仍然可以将其用作变量/参数名称，但您可能不应该这样做。