php - 将两个具有共同时间戳的表和每个月的总金额分组

Question

以日期为时间戳的第一笔收入和第二笔支出以及每个月的收入和支出总额，现在我想将其列在一张表格中，如下所示

Month | Income | Expense | Profit

到现在为止，我只能将一个表与总金额分组，但我需要一个可以同时处理两个表的查询。

我的查询是

$result = mysql_query("SELECT 
    date_on,
    MONTHNAME(FROM_UNIXTIME(date_on)) as expmonth,
    YEAR(FROM_UNIXTIME(date_on)) as expyear,
    sum(amount) as exp_total

    from finance_grdps_exp

    group by  expmonth,expyear order by date_on DESC")

    or die(mysql_error());  
    $no=0;   
    $countem = 0;
    while($row = mysql_fetch_array($result))
        {$no++;
            echo' 
            <tr class="gradeX">
                <td>'.
                $row['expmonth'].' '.$row['expyear'].'
                </td>
                <td>'.
                $row['exp_total'].'
                </td>
                <td>'.
                $row['income_total'].' /* not working as if now
                </td>
                <td>'.
                PROFIT.'/* not working as if now
                </td>
                </tr> 
                ';
                }

---

伙计们 样本日期基数是....

收入表....

姓名| 收入日期（时间戳）| 收入金额

经验表

名称|date_on（时间戳）|金额

谢谢

鲁本感谢您的回复....但我收到错误

...在这两种情况下我都收到错误---每个派生表都必须有自己的别名......

SELECT MONTHNAME(FROM_UNIXTIME(date_on)) as expmonth,
       YEAR(FROM_UNIXTIME(date_on)) as expyear,
       SUM(amount) as exp_total, 
       SUM(income_amount) as inc_total 
FROM(SELECT finance_grdps_exp.date_on AS date_on, 
            finance_grdps_exp.amount AS exp_amount, 
            0 AS inc_amount 
     UNION 
     SELECT finance_grdps_income.income_date AS date_on, 
            0 AS exp_amount, 
            finance_grdps_income.income_amount AS inc_amount) 
GROUP BY expyear, expmonth ORDER BY date_on DESC 

请帮忙

Answer 1

假设您有以下结构的两个表 finance_grdps_exp 和 finance_grdps_inc：

日期_on | 数量

1. 如果在一个表中没有两行在 date_on 中编码的年份和月份相同，则 date_on 仅包含年份和月份，即所有行的其他字段（日期和时间）都相同。

   您可以将它们与 INNER JOIN 构造结合起来：

   SELECT finance_grdps_exp.date_on AS date_on,
          finance_grdps_exp.amount AS exp_amount,
          finance_grdps_inc.amount AS inc_amount
   FROM finance_grdps_exp INNER JOIN finance_grdps_inc
   ON finance_grdps_exp.date_on = finance_grdps_inc.date_on
   

   结果结构是：

   日期_on | exp_amount | inc_amount

   然后让我们将您的想法应用于生成的结构：

   SELECT date_on,
          MONTHNAME(FROM_UNIXTIME(finance_grdps_exp_and_inc.date_on)) as expmonth,
          YEAR(FROM_UNIXTIME(finance_grdps_exp_and_inc.date_on)) as expyear,
          SUM(finance_grdps_exp_and_inc.exp_amount) as exp_total,
          SUM(finance_grdps_exp_and_inc.inc_amount) as inc_total
   
   FROM (SELECT finance_grdps_exp.date_on AS date_on,
                finance_grdps_exp.amount AS exp_amount,
                finance_grdps_inc.amount AS inc_amount
   FROM finance_grdps_exp INNER JOIN finance_grdps_inc
   ON finance_grdps_exp.date_on = finance_grdps_inc.date_on) AS finance_grdps_exp_and_inc
   
   GROUP BY expyear, expmonth ORDER BY date_on DESC
   

   mysql_query 给我们：

       [
         expmonth,
         expyear,
         exp_total /* expense per month */,
         inc_total /* income per month */
       ]
   

   为确保 INNER JOIN 语句的最大性能为两个表中的 date_on 字段创建索引。

2. 其他情况（使用 UNION SELECT）。

   SELECT MONTHNAME(FROM_UNIXTIME(finance_grdps_exp_and_inc.date_on)) as expmonth,
          YEAR(FROM_UNIXTIME(finance_grdps_exp_and_inc.date_on)) as expyear,
          SUM(finance_grdps_exp_and_inc.exp_amount) as exp_total,
          SUM(finance_grdps_exp_and_inc.inc_amount) as inc_total
   FROM(SELECT finance_grdps_exp.date_on AS date_on,
          finance_grdps_exp.amount AS exp_amount,
          0 AS inc_amount 
          FROM finance_grdps_exp
        UNION 
        SELECT finance_grdps_inc.date_on AS date_on,
          0 AS exp_amount,
          finance_grdps_inc.amount AS inc_amount
          finance_grdps_inc) AS finance_grdps_exp_and_inc
   GROUP BY expyear, expmonth ORDER BY date_on DESC