问问题
1655 次
3 回答
2
$uploadType = $_POST["uploadType"];
Then use $uploadType in your if statements. Variables in PHP always begin with a dollar sign.
In addition, use else if for the other conditions.
于 2012-05-08T23:58:52.167 回答
1
您缺少两个“其他”陈述 - 在视频之前和事实“如果”陈述之前。
于 2012-05-09T00:09:04.900 回答
0
uploadType在这里被用作常数。尝试替换uploadType为$_POST['uploadType'].
于 2012-05-09T00:00:20.423 回答