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我正在编写一个 ASP.NET/C# 项目,它是一个带有评论的简单博客页面。问题我在单击按钮时看到评论加载原始博客加载以及博客和评论,试图让它加载只选择的博客/评论。如果我尝试不在 page_load 中加载博客,或者只有在不回发时才这样做,则不会显示任何内容。任何帮助,将不胜感激。PS 我知道那里有很多博客引擎,但有特定的原因。

protected void Page_Init(object sender, EventArgs e)
{
    //ParseControls(GlobalVar.pathxsltver);
    //        BindInfo();
}
private void ParseControls(string myxslt)
{

    //load the data
    FileStream fs = new FileStream(Server.MapPath ( GlobalVar.compathver), FileMode.Open, FileAccess.Read, FileShare.ReadWrite);
    DataSet dset = new DataSet();
    dset.ReadXml(fs);
    fs.Close();
    XPathDocument xdoc = new XPathDocument(Server.MapPath(GlobalVar.pathver ));
    XmlDocument mydoc = new XmlDocument();
    XPathNavigator navigator = xdoc.CreateNavigator();
    XPathExpression expression = navigator.Compile("BlogItems/Blog");
    expression.AddSort("ID", XmlSortOrder.Descending, XmlCaseOrder.UpperFirst, string.Empty, XmlDataType.Text);
    XPathNodeIterator iterator = navigator.Select(expression);
    int TheCnt = 0;
    int cnt = GlobalVar.BlogCntDisplay;
    string st = "<BlogItems>";
    foreach (XPathNavigator item in iterator)
    {
        TheCnt++;
        string sid = item.SelectSingleNode("ID").Value;
        st = st + "<Blog id=\"" + sid + "\">" + item.InnerXml;
        st = st + "<ComCnt>" + MyFunc.CountComments (sid,dset) +  "</ComCnt></Blog>";
        if (TheCnt == cnt) { break; }
    }
    st = st + "</BlogItems>";
    mydoc.LoadXml(st);
    XslCompiledTransform transform = new XslCompiledTransform();
    XsltSettings settings = new XsltSettings(true,true);
    transform.Load(Server.MapPath(myxslt),settings,null);
    StringWriter sw = new StringWriter();
    transform.Transform(mydoc, null, sw);
    string result = sw.ToString();
    //remove namespace
    result = result.Replace("xmlns:asp=\"remove\"", "");
    //parse control
    Control ctrl = Page.ParseControl(result);
    //find control to add event handler
    //Boolean test =  phBlog.FindControl("btnComment2").i;
   phBlog.Controls.Add(ctrl);
    XmlNodeList  nList = mydoc.SelectNodes("//BlogItems/Blog/ID");
   foreach (XmlNode objNode in nList)
   { 
    Button btnComment = (Button) phBlog.FindControl("btnComment"+objNode.InnerText );
    btnComment.CommandArgument = objNode.InnerText ;
       btnComment.BorderWidth = 0 ;

    btnComment.Command += new CommandEventHandler(Button1_Click);
   }
}

protected void Page_Load(object sender, EventArgs e)
{

   //if (!Page.IsPostBack )
   //{ParseControls(GlobalVar.pathxsltver);}
    ParseControls(GlobalVar.pathxsltver);
   }

protected void Button1_Click(object sender, CommandEventArgs e)
{
    Label1.Text = "Comm hit : " + e.CommandArgument.ToString();
    ParseControls(GlobalVar.blogcommentsver ); 
}
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1 回答 1

1

你的问题有点含糊,但如果我理解正确,你想知道为什么当你只想处理按钮点击时整个页面会刷新?

每当您执行任何类型的回发(包括处理任何事件)时,都会重新呈现整个页面。不仅如此,您正在使用页面类的全新实例。旧的已经死了,走了。这就是网络正常工作的方式。

如果只想重新加载页面的一部分,则需要使用ajax。在 ASP.Net 领域,这意味着将您的评论部分放在可以刷新的 UpdatePanel 控件中。

于 2009-06-26T19:15:44.580 回答