php - PHP：在一个字符串中搜索数组中的所有子字符串，然后回显任何匹配项？

Question

$longString = "I walk in the park.";
$stringArray = array("walk", "park", "beach");

基本上，我想$longString搜索$stringArray. 所以在这种情况下，我想找到 walk 和 park 然后回显这些字符串。

这是可行的吗？多谢你们！

Answer 1

遍历数组并检查该字符串是否存在于长字符串中：

$longString = "I walk in the park and I like to jumprope.";
$stringArray = array("walk" => "walk", "park" => "park", "jumprope" => "jump rope");

foreach( $stringArray as $search => $print) {
    if( !(strpos( $longString, $search) === false)) {
        echo $print;
    }
}

演示

Answer 2

$longString = "I walk in the park.";
$stringArray = array("walk", "park", "beach");

foreach ($stringArray as $item) {
    if (stristr($longString, $item))
        echo $item . "<br>";
}

Answer 3

$longString = "I walk in the park.";
$stringArray = array{"walk", "park", "beach",);

foreach( $stringArray as $search) {
    if(strpos( $longString, $search) !== FALSE) {
        echo $search;
    }
}

Answer 4

当然，这是可能的：

$longString  = "I walk in the park.";
$stringArray = array("walk", "park", "beach");

foreach ($stringArray as $key => $val) {
    if (strpos($longString, $val) === false) {
        unset($stringArray[$key]);
    }
}

var_dump($stringArray);

$stringArray将仅包含出现在$longString.