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我正在 JSP 中构建一个页面，其中包含一个用于插入搜索查询的文本框的表单。单击搜索按钮时，它必须传递到一个 servlet，该 servlet 从文本框中收集术语并将其提交给 Google，然后收集结果并显示到我自己的页面中（例如，就在之前页面中的表单下方）。
任何人都可以建议我是否可以从 servlet 以编程方式将搜索参数传递给谷歌？

任何见解、建议或伪代码示例都将受到高度赞赏。

谢谢你。

4

1 回答 1

2

是的，虽然 Google 自定义搜索 API 查看概述和以下说明是可能的：

概述

使用 REST

Java 库和指南

我认为或多或少这就是你要找的东西：

package com.hahahaha.servlet;

import com.google.api.client.http.javanet.NetHttpTransport;
import com.google.api.client.json.jackson.JacksonFactory;
import com.google.api.services.customsearch.Customsearch;
import com.google.api.services.customsearch.model.Result;
import com.google.api.services.customsearch.model.Search;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.List;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 *
 * @author hahahahaha
 */
@WebServlet(name = "GoogleSearchServlet", urlPatterns = {"/GoogleSearchServlet"})
public class GoogleSearchServlet extends HttpServlet {

    /**
     * Processes requests for both HTTP
     * <code>GET</code> and
     * <code>POST</code> methods.
     *
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    protected void processRequest(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        response.setContentType("text/html;charset=UTF-8");
        PrintWriter out = response.getWriter();

        try {
            out.println("<html>");
            out.println("<head>");
            out.println("<title>Servlet GoogleSearchServlet</title>");
            out.println("</head>");
            out.println("<body>");

            // Get your query string posted by the user
            String query = request.getParameter("query");            
            //Instantiate a Customsearch object using NetHttpTransport and the JacksonFactory (JSON library)
            Customsearch customsearch = new Customsearch(new NetHttpTransport(), new JacksonFactory());
            // Instantiate a Customsearch.Cse.List object using your query string
            com.google.api.services.customsearch.Customsearch.Cse.List list = customsearch.cse().list(query);
            // Set your API KEY
            list.setKey("YOUR_API_KEY");
            // Set your custom search engine ID
            list.setCx("YOUR_CSEID");
            // Execute the search
            Search results = list.execute();
            // Get the result items
            List<Result> items = results.getItems();
            // Loop through your result items and stream them to the client            
            for(Result result : items){
                out.println("<b>" + result.getHtmlTitle() + "</b>");
            }                
            out.println("</body>");
            out.println("</html>");
        } finally {
            out.close();
        }
    }

    // <editor-fold defaultstate="collapsed" desc="HttpServlet methods. Click on the + sign on the left to edit the code.">
    /**
     * Handles the HTTP
     * <code>GET</code> method.
     *
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }

    /**
     * Handles the HTTP
     * <code>POST</code> method.
     *
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }

    /**
     * Returns a short description of the servlet.
     *
     * @return a String containing servlet description
     */
    @Override
    public String getServletInfo() {
        return "Short description";
    }// </editor-fold>
}
于 2012-05-08T14:55:08.673 回答