mysql - 在不使用 LIMIT 的情况下选择第 5 个最高值

Question

我是 SQL 新手，我想在不使用 LIMIT 的情况下获取第 5 个最高值。这是我正在尝试的代码，但它无法正常工作。它显示的是第 5 个最低值，而不是第 5 个最高值。

SELECT a . * FROM user AS a 
WHERE 5 = 
(SELECT count( DISTINCT b.id ) FROM user  AS b WHERE b.id >= a.id ORDER BY a.id DESC)

谁能帮我这个？

Answer 1

你也可以这样做：

SET @nth := 5;
SELECT
    a.*
FROM jos_modules AS a
WHERE  @nth = ( 
    SELECT 
        COUNT(b.id) 
    FROM user AS b
    WHERE 
        a.id >= b.id
);

Answer 2

尝试这个

SELECT a . *
FROM user AS a
WHERE 5 = (
SELECT count( DISTINCT b.id )
FROM user AS b
WHERE a.id >= b.id ORDER BY a.id )

Answer 3

select * from (
select a.* , row_number() over (order by id asc) as RANK
from a ) where RANK=5 ;

如果您使用的是 Teradata DB，则可以使用限定语句：

select * from a 
qualify row_number () over(order by id asc)=5;