php - 从 $_SESSION 获取 var 会引发错误

Question

在传递$_SESSION['var']给函数时，如果$_SESSION['var']未设置，我会收到通知：

Notice: Undefined index: var in scripname.php on line 49

有没有更安全的方法来获取，如果未设置$_SESSION['var']，这会给我吗？0$_SESSION['var']

先感谢您！！

score 5 · Accepted Answer

5

$var = isset($_SESSION['var']) ? $_SESSION['var'] : 0

于 2012-05-08T07:41:48.813 回答

score 3 · Accepted Answer

3

if (isset($_SESSION['var']))
{
    echo "session is set";
}
else
{
    echo "session is not set";
}

于 2012-05-08T08:01:05.553 回答

score 1 · Accepted Answer

1

if (isset($_SESSION['var'])){
    // Do something
}

于 2012-05-08T07:41:40.723 回答

score 0 · Accepted Answer

0

if(!array_key_exists('var',$_SESSION))
{
    $var = 0;
}
else
{
    $var = $_SESSION['var'];
}

于 2012-05-08T07:41:51.580 回答

score 0 · Accepted Answer

0

采用

if(isset($_SESSION['var']))
    // do

于 2012-05-08T07:42:04.203 回答

score 0 · Accepted Answer

0

怎么样：

$var = @$_SESSION['var'];

于 2012-05-08T07:51:28.367 回答

6 回答 6