我只需要通过响应是png图片来解密来自httpresponse的响应,所以我这样做了:
HttpPost httppost = new HttpPost(tileURLString);
nameValuePairs.add(new BasicNameValuePair("x", String.valueOf(ValueX)));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
如果我得到回应
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
if (entity == null) {
Log.i("Error","No content download");
}
InputStream in = entity.getContent();
这是工作。但我需要将此输出作为字符串使用 xor 解密,所以我所做的只是:
String responseText = EntityUtils.toString(response.getEntity());
InputStream in = new ByteArrayInputStream(responseText.getBytes());
PS。这仍然不能解密正常的输入流,但没有奏效。我google了一天。请帮帮我。如果这项工作我将进入下一步(解密)。提前致谢。
编辑:或者我使用这个方法将 InputStream 转换为字符串
private String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(
new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append((line + "\n"));
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
然后我用它来转换回输入流,但它也没有用。
public InputStream convertStringToStream(String text)
throws UnsupportedEncodingException {
return new ByteArrayInputStream(text.getBytes("UTF-8"));
}