10

假设我有这些列

 uniqueID|Money|Quantity|MoneyOrder|QuantityOrder
1|23|12||
2|11|9||
3|99|100||

我想要做的是更新MoneyOrderQuantityOrder基于ORDER BY.

所以结果将是:

uniqueID|Money|Quantity|MoneyOrder|QuantityOrder
1|23|12|2|1
2|11|90|1|2
3|99|100|3|3

我希望更新像身份列一样运行,而不是实际使其成为身份列。我知道我可以按“x”排序,订单就是结果,但我想生成一个报告,您可以在其中逐行查看项目。

这样的事情可能update mytable set Moneyorder = 'imnotsure' order by MoneyOrder asc吗?

4

2 回答 2

43
SET @rownumber = 0;    
update mytable set Moneyorder = (@rownumber:=@rownumber+1)
order by MoneyOrder asc

或在单个查询中执行此操作,您可以尝试

update mytable target
join
(
     select id, (@rownumber := @rownumber + 1) as rownum
     from mytable         
     cross join (select @rownumber := 0) r
     order by MoneyOrder asc
) source on target.id = source.id    
set Moneyorder = rownum
于 2012-05-07T16:41:01.220 回答
7

查看此问题的答案:

更新列以使其包含行位置

SET @counter = 0;

UPDATE 
my_table
SET MoneyOrder = @counter := @counter + 1
ORDER BY Money;

SET @counter = 0;

UPDATE 
my_table
SET QuantityOrder = @counter := @counter + 1
ORDER BY Quantity;
于 2012-05-07T16:42:32.107 回答