这是一个使用该PIVOT
函数的简单查询。如果您有一些已知要转换为列的值,则可以使用静态版本:
create table yourtable
(
cost varchar(10),
rate int
);
insert into yourtable values
('Repair', 12),
('Repair', 223),
('Wear', 1000),
('Wear', 666),
('Fuel', 500),
('Repair', 600),
('Fuel', 450),
('Wear', 400);
select *
from
(
select cost, rate
from yourtable
) x
pivot
(
sum(rate)
for cost in ([Repair], [Wear], [Fuel])
) p;
如果您有未知数量的值,则可以使用动态 SQL 创建动态数据透视:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(cost)
from yourtable
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT ' + @cols + ' from
(
select cost, rate
from yourtable
) x
pivot
(
sum(rate)
for cost in (' + @cols + ')
) p '
execute(@query)
请参阅SQL Fiddle with Demo。两者都会产生相同的结果。