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我在调用此 SQL 命令时遇到问题,我得到:'OperationalError: near "'0-0'": syntax error'

我的电话如下:

users_db_curs.execute("INSERT INTO `"+table_name+"` (uID, username, password, creator_exp, location) 
VALUES ('"+user_ID+"', '"+username+"', '"+password+"', '"+creator_exp+"', '0-0')")
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2 回答 2

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我测试了你的语句,如果你的不同变量的格式正确,可以直接连接到语句字符串中,它应该可以正常工作:

>>> import sqlite3
>>> conn = sqlite3.connect(':memory:')
>>> cu = conn.cursor()
>>> cu.execute('create table foo (uID, username, password, creator_exp, location)')
<sqlite3.Cursor object at 0x7fccc2c115e0>
>>> user_ID='a'
>>> username='b'
>>> password='c'
>>> creator_exp='d'
>>> table_name='foo'
>>> cu.execute("INSERT INTO `"+table_name+"` (uID, username, password, creator_exp, location) VALUES ('"+user_ID+"', '"+username+"', '"+password+"', '"+creator_exp+"', '0-0')")
<sqlite3.Cursor object at 0x7fccc2c115e0>

当你得到它时可能不是syntax error这样:

>>> username="'barf"
>>> cu.execute("INSERT INTO `"+table_name+"` (uID, username, password, creator_exp, location) VALUES ('"+user_ID+"', '"+username+"', '"+password+"', '"+creator_exp+"', '0-0')")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
sqlite3.OperationalError: near "barf": syntax error

因此,只需使用格式化参数即可。

>>> cu.execute("INSERT INTO `"+table_name+"` (uID, username, password, creator_exp, location) VALUES (?, ?, ?, ?, '0-0')", 
(user_ID, username, password, creator_exp))
<sqlite3.Cursor object at 0x7fccc2c115e0
于 2012-05-06T10:18:40.777 回答
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con = sqlite.connect(db_name)
cur = con.cursor()

with con:
   cur.execute("INSERT INTO ? VALUES(?, ?, ?, ?, ?)",
       (table_name, user_ID, username, password, creator_exp))

应该可以工作
你应该阅读Zetcode 的教程

于 2012-05-06T10:16:19.687 回答