sql - 在对行进行分组时需要帮助

Question

可能重复：
如何在 Oracle 中将多行组合成逗号分隔的列表？

我有一个以下列方式存储数据的表-

60333,120102,20120502,010000,1,2

60333,120102,20120502,020000,3,4 

60333,120102,20120502,030000,5,6 

60333,120102,20120502,040000,7,8 

61663,120103,20120502,010000,9,10 

61663,120103,20120502,020000,11,12 

61663,120103,20120502,030000,13,14 

61663,120103,20120502,040000,15,16 

60333,120102,20120503,010000,17,18 

60333,120102,20120503,020000,19,20 

60333,120102,20120503,030000,21,22 

60333,120102,20120503,040000,23,24 

我预计会显示如下输出：

60333,120102,20120502,1,2,3,4,5,6,7,8

60333,120102,20120503,17,18,19,20,21,22,23,24

61663,120103,20120502,,9,10,11,12,13,14 ,15,16

对于唯一的 60333、120102 和 Date，所有数据都需要显示在一行而不是 4 行中。

Answer 1

尝试这个：

select a, b, c, listagg(e || ',' || f, ',') WITHIN GROUP (ORDER BY e) as x
from tbl
group by a, b, c

现场测试：http ://www.sqlfiddle.com/#!4/40a4b/13

Answer 2

如果我们假设：

1. 第 4 列只能取 4 个值 (010000,020000,030000,040000) 和
2. 您希望输出中始终包含 11 列

那么你需要"pivot query"，它是这样的：

select c1, c2, c3, 
    max(decode(c4, '010000', c5)) as c5for010000,
    max(decode(c4, '010000', c6)) as c6for010000,
    max(decode(c4, '020000', c5)) as c5for020000,
    max(decode(c4, '020000', c6)) as c6for020000,
    max(decode(c4, '030000', c5)) as c5for030000,
    max(decode(c4, '030000', c6)) as c6for030000,
    max(decode(c4, '040000', c5)) as c5for040000,
    max(decode(c4, '040000', c6)) as c6for040000
my_table
group by c1, c2, c3;