bash - 从文件中复制文件列表

Question

我的文件包含由行尾分隔的文件列表

$ cat file_list
file1
file2
file3

我想用 FTP 复制这个文件列表

我怎样才能做到这一点 ？我必须写一个脚本吗？

Answer 1

You can turn your list of files into list of ftp commands easily enough:

(echo open hostname.host; 
 echo user username; 
 cat filelist | awk '{ print "put " $1; }'; 
echo bye) > script.ftp

Then you can just run:

ftp -s script.ftp

Or possibly (with other versions of ftp)

ftp -n < script.ftp

Answer 2

Something along these lines - the somecommand depends on what you want to do - I don't get that from your question, sorry.

#!/bin/bash
# Iterate through lines in file
for line in `cat file.txt`;do
#your ftp command here do something    
 somecommand $line
done

edit: If you really want to persue this route for multiple files (you shouldn't!), you can use the following command in place of somecommand $line:

ncftpput -m -u username -p password ftp.server.com /remote/folder $line

ncftpput propably also takes an arbitrary number of files to upload in one go, but I havn't checked it. Notice that this approach will connect and disconnect for every single file!

Answer 3

感谢有关如何将文件列表提供给 ftp 的非常有用的示例。这对我来说效果很好。

在 Linux (CentOs 5.5) 中创建我的 ftp 脚本后，我运行该脚本：

ftp –n < ../script.ftp

我的脚本（更改名称以保护无辜者）开头是：

open <ftpsite>
user <userid> <passwd>
cd <remote directory>
bin
prompt
get <file1>
get <file2>

并以：

get <filen-1>
get <filen>
bye