0

下面的查询可以很好地返回为空的列名，我想要完成的是让它返回到具有空值的第一个列名。我还有另一列名为 email 的每一行都有一个唯一的电子邮件地址。我的问题是我无法弄清楚执行此操作的适当语法。任何帮助表示赞赏！

我也为此使用php5.2。

 SELECT col FROM (SELECT 'GAME0' AS col, GAME0 AS value FROM USERNAME
       UNION ALL SELECT 'GAME1', GAME1 FROM USERNAME
       UNION ALL SELECT 'GAME2', GAME2 FROM USERNAME
       UNION ALL SELECT 'GAME3', GAME3 FROM USERNAME
       UNION ALL SELECT 'GAME4', GAME4 FROM USERNAME
       UNION ALL SELECT 'GAME5', GAME5 FROM USERNAME
       UNION ALL SELECT 'GAME6', GAME6 FROM USERNAME
       UNION ALL SELECT 'GAME7', GAME7 FROM USERNAME
       UNION ALL SELECT 'GAME8', GAME8 FROM USERNAME
       UNION ALL SELECT 'GAME9', GAME9 FROM USERNAME
       UNION ALL SELECT 'GAME10', GAME10 FROM USERNAME
       UNION ALL SELECT 'GAME11', GAME11 FROM USERNAME
       UNION ALL SELECT 'GAME12', GAME12 FROM USERNAME
       UNION ALL SELECT 'GAME13', GAME13 FROM USERNAME
       UNION ALL SELECT 'GAME14', GAME14 FROM USERNAME
       UNION ALL SELECT 'GAME15', GAME15 FROM USERNAME
       UNION ALL SELECT 'GAME16', GAME16 FROM USERNAME
       UNION ALL SELECT 'GAME17', GAME17 FROM USERNAME
       UNION ALL SELECT 'GAME18', GAME18 FROM USERNAME
       UNION ALL SELECT 'GAME19', GAME19 FROM USERNAME
    ) allValues 
    WHERE value is null and email='emailaddress'

编辑：如果不需要上面的查询，我需要类似下面的东西，我可以在其中更改第一个空值的值。再次语法是我最大的问题。

update username
SET CASE GAME0
    WHEN GAME0 IS NOT NULL THEN GAME1
    WHEN GAME1 IS NOT NULL THEN GAME2
    WHEN GAME2 IS NOT NULL THEN GAME3
    WHEN GAME3 IS NOT NULL THEN GAME4
    WHEN GAME4 IS NOT NULL THEN GAME5
    WHEN GAME5 IS NOT NULL THEN GAME6
    WHEN GAME7 IS NOT NULL THEN GAME8
    WHEN GAME8 IS NOT NULL THEN GAME9
    WHEN GAME9 IS NOT NULL THEN GAME10
    WHEN GAME10 IS NOT NULL THEN GAME11
    WHEN GAME11 IS NOT NULL THEN GAME12
    WHEN GAME12 IS NOT NULL THEN GAME13
    WHEN GAME13 IS NOT NULL THEN GAME14
    WHEN GAME14 IS NOT NULL THEN GAME15
    WHEN GAME15 IS NOT NULL THEN GAME16
    WHEN GAME16 IS NOT NULL THEN GAME17
    WHEN GAME17 IS NOT NULL THEN GAME18
    WHEN GAME18 IS NOT NULL THEN GAME19
  END where EMAIL='emailaddress'
4

2 回答 2

3

你可以使这个查询更简单，并通过 php 进行一些计算：

$arr_field = array();
foreach(range(0, 19) as $i)
    $arr_field[] = "GAME{$i}";

$str_add = implode(' + ', $arr_field);
$str_select = implode(', ', $arr_field);

$query = 
mysql_query("
    SELECT {$str_select}
    FROM USERNAME
    WHERE ({$str_add}) IS NULL AND email = 'emailaddress'
");

// Then get the NULL column through a loop

while($row = mysql_fetch_assoc($query))
    foreach($arr_field as $h)
        if ( ! isset($row[$h])) {

            echo "Found column! {$h}<br />";
            break;

        }

很显然，我将所有 20 个字段加在一起，如果这 20 个值中的任何一个为 NULL，则结果变为 NULL。我获取所有 20 个值，然后通过 php 循环查找 NULL 字段。

不过老实说，我会制作另一个结构，用第二个表来处理这些 GAME0 - GAME19 字段。

于 2012-05-03T08:20:03.167 回答
1

我不太了解您的表结构，但这是一种简单的方法：只需添加order by col limit 1到您的查询中。

编辑：为此，您必须使用"GAME00", "GAME01"等。（您不必更改列名，只需更改您在字符串中放置的名称）

编辑 2：要包含它必须存在于您的子查询中的电子邮件地址，如下所示：

SELECT col FROM (SELECT 'GAME00' AS col, GAME0 AS value, email FROM USERNAME
   UNION ALL SELECT 'GAME01', GAME1, email FROM USERNAME

（ETC）

于 2012-05-03T08:08:21.017 回答