1

我正在处理图片上传表单。当用户上传图片时。在预览区域中使用 ajax 显示该图像...表单重新加载，但似乎不想显示新头像。我得到一个CSRF verification failed. Request aborted错误。

Reason given for failure: CSRF is missing or incorrect.

我在表单中有一个 csrf_token。

模板： 

<form class="nice inline-form" enctype="multipart/form-data" method="POST" action="/profile/edit/" id="avatarLoadForm">
      <input type="hidden" name="next" value="/account/settings/">
      {% csrf_token %}
      <div>
      <label for="avatar">Avatar</label>
      <div id="preview" class="frame">  
           <img src="{% if profile.user %}{% thumbnail profile.avatar 120x120 crop %}{% else %}{{ DEFAULT_AVATAR }}{% endif %}" alt="" alt="sample-pic" id="thumb" />
      </div>
      <input type="file" size="20" id="imageUpload">
      and other form info...
</form>

阿贾克斯/jQuery：

$(document).ready(function(){

        var thumb = $('img#thumb'); 

        new AjaxUpload('imageUpload', {
            action: $('#avatarLoadForm').attr('action'),
            name: 'avatar',
            csrfmiddlewaretoken: $( "#csrfmiddlewaretoken" ).val(),

            onSubmit: function(file, extension) {
                $('#preview').addClass('loading');
            },
            onComplete: function(file, response) {
                thumb.load(function(){
                    $('#preview').removeClass('loading');
                    thumb.unbind();
                });
                thumb.attr('src', response);

            } 

        });

也许我的Views.py中缺少一些东西？

@login_required        
def edit_profile(request):
    context = base_context(request)
    if request.method == 'POST':
        notify = "You have successfully updated your profile."
        user_info_form = UserInfoForm(request.POST, request.FILES)
        if user_info_form.is_valid():
            if request.is_ajax():
                response = simplejson.dumps({"status": "Upload Success"})
                return HttpResponse (response, mimetype='application/json')
            messages.success(request, 'You have successfully updated your profile.')
            user_info_form.save(request.user, profile_type)
            return HttpResponseRedirect(request.POST.get('next', '/profile/' + request.user.username + '/'))
    else:
        initial = {}
        initial['first_name'] = request.user.first_name
        initial['last_name'] = request.user.last_name
        initial['email'] = request.user.email
        initial['about'] = profile.about
        initial['country'] = profile.country
        initial['about'] = profile.about
        user_info_form = UserInfoForm(initial=initial)
    context['user_info_form'] = user_info_form
    context['profile'] = profile
    return render_to_response('settings/profile.html', context, context_instance=RequestContext(request))

设置.py：

MIDDLEWARE_CLASSES = (
    'django.middleware.common.CommonMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.middleware.csrf.CsrfResponseMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    'pagination.middleware.PaginationMiddleware',
)

文件上传工作没有 ajax 废话。也就是说，它实际上保存了图像，只是没有在预览中显示它。我真的不知道出了什么问题，也不知道为什么会这样。有很多关于 csrf 失败的帖子。但我找不到适合这种情况的。任何见解将不胜感激。

4

4 回答 4

3

是什么让您认为 csrf 令牌具有 id #csrfmiddlewaretoken？快速查看您呈现的 html 会发现模板标签不会生成 id 属性。

试试$("input[name=csrfmiddlewaretoken]").val()吧

于 2012-05-01T22:19:55.260 回答
0 
csrfmiddlewaretoken: $( "#csrfmiddlewaretoken" ).val(),

这可能行不通。CSRF 字段的名称/id 是动态生成的，而不是像这样的静态字符串。

请参阅https://docs.djangoproject.com/en/1.3/ref/contrib/csrf/#ajax了解如何正确使用带有 AJAX 请求的 CSRF 中间件。

于 2012-05-01T22:15:26.130 回答
0

看到这个http://djangolinks.com/detail/ajax-post-requests-csrf-fix-69/

于 2012-05-02T07:02:02.093 回答
0

这对我有用：

beforeSend: function(jqXHR, settings) {
    jqXHR.setRequestHeader('X-CSRFToken', $('input[name=csrfmiddlewaretoken]').val());
},

或者，您可以像这样从 dom 中提取 cookie，如果您的表单是通过 ajax 生成的，并且由于其呈现方式而无法发送 {{ csrf_token }}，那就太好了：

beforeSend: function(xhr, settings) {
        console.log('-------------before send--');
        function getCookie(name) {
            var cookieValue = null;
            if (document.cookie && document.cookie != '') {
                var cookies = document.cookie.split(';');
                for (var i = 0; i < cookies.length; i++) {
                    var cookie = jQuery.trim(cookies[i]);
                    // Does this cookie string begin with the name we want?
                if (cookie.substring(0, name.length + 1) == (name + '=')) {
                    cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
                    break;
                }
            }
        }
        return cookieValue;
        }
        if (!(/^http:.*/.test(settings.url) || /^https:.*/.test(settings.url))) {
            // Only send the token to relative URLs i.e. locally.
            xhr.setRequestHeader("X-CSRFToken", getCookie('csrftoken'));
        }
}
于 2013-02-14T00:06:27.117 回答