python - 如何用 BeautifulSoup 和 Regex 解析这个 HTML 表？

Question

我的 HTML：

            <table cellspacing="0" cellpadding="2" rules="all" border="1" id="branchTable" width="100%">
            <tr class="TitleTable">
                <th scope="col" width="250"><b>Branch Name</b></th><th scope="col" width="35%"><b>Branch Date</b></th><th scope="col" width="35%"><b>Branch Origin</b></th>
            </tr><tr class="RowSet">
                <td><a class="blue" href="javascript: OpenWindow(&#39;/home/data/files/fetchRecord.php?fileID=342&#39;)">SFO Branch</a></td><td class="red">03/16/2012</td><td class="red">&nbsp;</td>
            </tr><tr class="RowSet">
                <td><a class="blue" href="javascript: OpenWindow(&#39;/home/data/files/fetchRecord.php?fileID=884&#39;)">LAX Branch</a></td><td class="red">03/16/2012</td><td class="red">06/16/1985</td>
            </tr><tr class="RowSet">
                <td><a class="blue" href="javascript: OpenWindow(&#39;/home/data/files/fetchRecord.php?fileID=83&#39;)">DC Branch</a></td><td class="red">03/16/2012</td><td class="red">&nbsp;</td>
            </tr>
            </table>

到目前为止我的代码：

from BeautifulSoup import BeautifulSoup

soup = BeautifulSoup(pageSource)
table = soup.find("table", id = "branchTable")
rows = table.findAll("tr", {"class":"RowSet"})

data = [[td.findChildren(text=True) for td in tr.findAll("td")] for tr in rows]
print data

输出 ：

SFO Branch  03/16/2012   
LAX Branch  03/16/2012  06/16/1985
DC Branch   03/16/2012   

期望：

我想获取标签中包含的数据以及 ID (fetchRecord.php?fileID= 342 )。不确定如何获取该值。BeautifulSoup 或正则表达式，请帮忙。谢谢！

Answer 1

您可以使用正则表达式来解析，href但我懒得写。请参阅href_parse下面的检索 URI 后解析查询字符串的正确方法：

from urlparse import urlparse
from urlparse import parse_qs

def href_parse(value):
    if (value.startswith('javascript: OpenWindow('') and 
        value.endswith('')'):
        begin_length = len('javascript: OpenWindow('')
        end_length = len('')')
        file_location = value[begin_length:-end_length]

        query_string = urlparse(file_location).query
        query_dict = parse_qs(query_string)
        return query_dict.get('fileId', None)


href_data = [[href_parse(td.find('a', attrs={'class': 'blue'})['href']) 
              for td in tr.findAll("td")] 
              for tr in rows]
print href_data

Answer 2

这个怎么样

import re
urlRE = re.compile('javascript: OpenWindow\(\'(.*)#39;\)')
...
urlMat = urlRE.match(value)
if urlMat:
   url = urlMat.groups()[0]