我不明白 - 如果我检查函数中命令的退出状态并将其存储在局部变量中,我总是得到答案 0。从函数外部,我得到正确的退出状态。
#!/bin/bash
function check_mysql()
{
local output=`service mysql status`
local mysql_status=$?
echo "local output=$output"
echo "local status=$mysql_status"
}
check_mysql
g_output=`service mysql status`
g_mysql_status=$?
echo "g output=$g_output"
echo "g status=$g_mysql_status"
输出是:
local output=MySQL is running but PID file could not be found..failed
local status=0
g output=MySQL is running but PID file could not be found..failed
g status=4
4的状态是正确的。