mysql - MySQL按天计数和分组

Question

我有以下结构

ID    DATE(DATETIME)         TID
1     2012-04-01 23:23:23    8882

我正在尝试计算行数并按每月匹配 TID = 8882 的每一天对它们进行分组

谢谢

Answer 1

您可以使用DAY功能进行分组：

SELECT DAY(Date), COUNT(*)
FROM table
WHERE TID = 8882
GROUP BY DAY(Date)

Answer 2

不确定您所说的月份中的某天是什么意思——您想将 2 月 1 日与 3 月 1 日归为一组吗？或者你只是说约会？假设后者，这个怎么样：

SELECT DATE(date) as d,count(ID) from TABLENAME where TID=8882 GROUP by d;

Answer 3

试试这个查询：

SELECT COUNT(id), DAY(dat), MONTH(dat), YEAR(dat) 
FROM table
WHERE TID=8882
GROUP BY YEAR(dat), MONTH(dat), DAY(dat);

Answer 4

尝试这个：

SELECT DAY(date) AS `DAY`,  COUNT(1) AS `COUNT` FROM
table1 
    WHERE TID = 8882
GROUP BY DAY(date)

MySQL Query GROUP BY 日/月/年怎么样

Answer 5

计算每个日期：

SELECT date(created_at), COUNT(*)
FROM message_requests
GROUP BY date(created_at)