6

我有三个 MySQL 表——照片、标签和标签照片——以及照片和标签之间的 m:n 关系。

Photos:     id | filename | ...
Tags:       id | name
Tagsphotos: photo | tag

我想选择所有具有这种条件的照片：

(tagged as "dirty" AND tagged as "road") AND (tagged as "light.front" OR tagged as "light.side") AND (tagged as "perspective.two-point")

...这意味着我想找到所有带有脏路的照片，采用两点透视法，无论是侧光还是前光。

我该怎么做？谢谢。

4

3 回答 3

3

我认为您将不得不将标签表加入照片表四次......非常丑陋。

SELECT Photos.*
FROM
  Photos
  JOIN (
    Tagsphotos JOIN Tags ON (Tags.id = Tagsphotos.tag)
  ) t1 ON (t1.photo = Photos.id)
  JOIN (
    Tagsphotos JOIN Tags ON (Tags.id = Tagsphotos.tag)
  ) t2 ON (t2.photo = Photos.id)
  JOIN (
    Tagsphotos JOIN Tags ON (Tags.id = Tagsphotos.tag)
  ) t3 ON (t3.photo = Photos.id)
  JOIN (
    Tagsphotos JOIN Tags ON (Tags.id = Tagsphotos.tag)
  ) t4 ON (t4.photo = Photos.id)
WHERE
      (t1.name = 'dirty' AND t2.name = 'road')
  AND (t3.name = 'light.front' OR t3.name = 'light.side')
  AND (t4.name = 'perspective.two-point')

子查询可能会更快：

SELECT *
FROM Photos
WHERE
  Photos.id IN (
    SELECT Tagspohotos.photo
    FROM Tagsphotos JOIN Tags ON (Tags.id = Tagsphotos.tag)
    WHERE Tags.name = 'dirty'
  )
  AND Photos.id IN (
    SELECT Tagspohotos.photo
    FROM Tagsphotos JOIN Tags ON (Tags.id = Tagsphotos.tag)
    WHERE Tags.name = 'road'
  )
  AND Photos.id IN (
    SELECT Tagspohotos.photo
    FROM Tagsphotos JOIN Tags ON (Tags.id = Tagsphotos.tag)
    WHERE Tags.name = 'light.front' OR Tags.name = 'light.side'
  )
  AND Photos.id IN (
    SELECT Tagspohotos.photo
    FROM Tagsphotos JOIN Tags ON (Tags.id = Tagsphotos.tag)
    WHERE Tags.name = 'perspective.two-point'
  )
于 2012-04-30T12:37:55.327 回答
1

抱歉，我没有意识到您正在使用 MySQL - 下面给出了更新的答案。

假设每个标签只能为每张照片指定一次（即一张照片不能被多次标记为“脏”）：

SELECT      P.id,
            P.[filename]
FROM        Photos P
INNER JOIN  Tagsphotos TP ON TP.photo = P.id
INNER JOIN  Tags T ON TP.tag = T.id
INNER JOIN  (
        SELECT  'dirty' name,
                10 [weight]
        UNION
        SELECT  'road' name,
                10 [weight]
        UNION
        SELECT  'perspective.two-point' name,
                10 [weight]
        UNION
        SELECT  'light.front' name,
                1 [weight]
        UNION
        SELECT  'light.side' name,
                1 [weight]
) R ON T.name = R.name
GROUP BY    P.id,
            P.[filename]
HAVING  SUM(R.[weight]) >= 31
于 2012-04-30T12:42:00.983 回答
0

假设照片和标签列是 id：

select p.* from Photos p, Tags t, Tagsphotos tp
where p.id = tp.photo and t.id = tp.tag
and t.tagged in ("dirty", "road", "perspective.two-point", "light.front")
group by p.photo
having count(distinct t.tagged) = 4

UNION

select p.* from Photos p, Tags t, Tagsphotos tp
where p.id = tp.photo and t.id = tp.tag
and t.tagged in ("dirty", "road", "perspective.two-point", "light.side")
group by p.photo
having count(distinct t.tagged) = 4
于 2012-04-30T12:36:23.007 回答