谁能帮我解决这个问题?我需要将公钥转换为BigInteger
. 这里的公钥是ECPoint
曲线上的一个点(x,y)
。我不知道如何将其转换为BigInteger
. 请帮我。这是我的代码:
public static void main(String[] args) throws Exception {
Security.addProvider(new BouncyCastleProvider());
ECCurve curve = new ECCurve.Fp(
new BigInteger("883423532389192164791648750360308885314476597252960362792450860609699839"), // q
new BigInteger("7fffffffffffffffffffffff7fffffffffff8000000000007ffffffffffc", 16), // a
new BigInteger("6b016c3bdcf18941d0d654921475ca71a9db2fb27d1d37796185c2942c0a", 16)); // b
ECParameterSpec ecSpec = new ECParameterSpec(
curve,
curve.decodePoint(Hex.decode("020ffa963cdca8816ccc33b8642bedf905c3d358573d3f27fbbd3b3cb9aaaf")), // G
new BigInteger("883423532389192164791648750360308884807550341691627752275345424702807307")); // n
KeyPairGenerator kpg = KeyPairGenerator.getInstance("ECDSA", "BC");
kpg.initialize(ecSpec, new SecureRandom());
KeyPair keyPair = kpg.generateKeyPair();
PublicKey pubKey = keyPair.getPublic();
System.out.println(pubKey);
PrivateKey privKey = keyPair.getPrivate();
System.out.println(privKey);
BigInteger s = ((ECPrivateKey) privKey).getS();
System.out.println(s);
java.security.spec.ECPoint a = ((ECPublicKey) pubKey).getW();
}