这是你想要的吗?
template <typename T>
class foo
{
T* data;
public:
void operator<<(T t);
};
template <>
class foo<char>
{
public:
void operator<<(char* str);
};
如果你打算继承行为,你需要这样的东西:
template <typename T>
class foo_impl
{
T* data;
public:
void operator<<(T t);
};
template <typename T>
class foo : public foo_impl<T>
{
};
template <>
class foo<char> : public foo_impl<char>
{
public:
void operator<<(char* str);
};
(或者,通过消除不必要的出现更简单public
)
template <typename T>
class foo_impl
{
T* data;
public:
void operator<<(T t);
};
template <typename T>
struct foo : foo_impl<T>
{
};
template <>
struct foo<char> : foo_impl<char>
{
void operator<<(char* str);
};
我会建议一些 const 正确性:
template <typename T>
class foo_impl
{
T* data;
public:
void operator<<(const T& t);
};
template <typename T>
struct foo : foo_impl<T>
{
};
template <>
struct foo<char> : foo_impl<char>
{
void operator<<(const char* str);
};