2

我创建了自定义属性并放置在 Core.dll 中。

public class DBColumnReference : Attribute
{
    string m_column;


    public string ColumnName {
        get { return m_column; }

    }

    public DBColumnReference(string column)
    {
        m_column = column;
    }
}

然后我创建了我的应用程序，它引用了 Core.dll。
在我的应用程序中创建了自己的对象，并且在某些属性上使用来自 Core.dll 的自定义属性。 

public class TestingObject4
{
    string m_table = "TESTING_CORE_OBJECT4";

    public string Table 
    {
        get { return m_table; }
    }


    private int m_id = 0;

    [DBColumnReference("ID")]
    public int Id 
    {
        get { return m_id; }
        set { m_id = value; }
    }

我调用核心方法“FilterProperties(typeof(TestingObject4))”，它按属性过滤属性。

private static Dictionary<string, PropertyInfo> FilterProperties(Type type)
{
  Dictionary<string, PropertyInfo> result = new Dictionary<string, PropertyInfo>();
  if(type == null)
    return result;

  PropertyInfo[] properties = type.GetProperties();
  foreach(PropertyInfo prop in properties)
  {
   // Attribute[] atributes = Attribute.GetCustomAttributes(prop,   true);
    object[] atributes = prop.GetCustomAttributes(typeof(DBColumnReference), true);
    if(atributes != null && atributes.Length != 0)
    {
      DBColumnReference reference = atributes[0] as DBColumnReference;
      result.Add(reference.ColumnName, prop);
    }
  }
  return result;
}

并且Attributes[]属性始终为空。如何正确获取属性？

4

1 回答 1

1

试试这个对我有用的片段！

public class DBColumnReference : Attribute
{
    string m_column;


    public string ColumnName
    {
        get { return m_column; }

    }

    public DBColumnReference(string column)
    {
        m_column = column;
    }
}
public class TestingObject4
{
    string m_table = "TESTING_CORE_OBJECT4";

    public string Table
    {
        get { return m_table; }
    }


    private int m_id = 0;

    [DBColumnReference("an integer id")]
    public int Id
    {
        get { return m_id; }
        set { m_id = value; }
    }
}
class Program
{
    private static Dictionary<string, PropertyInfo> FilterProperties(Type type)
    {
        Dictionary<string, PropertyInfo> result = new Dictionary<string, PropertyInfo>();
        if (type == null)
            return result;

        PropertyInfo[] properties = type.GetProperties();
        foreach (PropertyInfo prop in properties)
        {
            // Attribute[] atributes = Attribute.GetCustomAttributes(prop,   true);
            object[] atributes = prop.GetCustomAttributes(typeof(DBColumnReference), true);
            if (atributes != null && atributes.Length != 0)
            {
                DBColumnReference reference = atributes[0] as DBColumnReference;
                result.Add(reference.ColumnName, prop);
            }
        }
        return result;
    }

    static void Main(string[] args)
    {
        Dictionary<string, PropertyInfo> resultCollection = FilterProperties(typeof(TestingObject4));
        foreach (var singleObject in resultCollection)
        {
            Console.WriteLine(singleObject.Key + "  " + singleObject.Value);
        }
        Console.ReadKey(false);
    }
}
于 2012-05-08T09:55:00.040 回答