我必须使用 C++ 制作地址簿，并且应该包含类和继承的类。主类包含姓名和地址，继承的教师类包含教师电话号码和 CNIC，员工类包含电话和 CNIC，学生类包含学生 ID 和电话。我用 C++ 编写了一个程序，但这总是会覆盖以前的数据。我被困在这里。我需要一个头骨程序或简单的算法来引导我前进。
这是我的代码。
// new.cpp : Defines the entry point for the console application.
// Address Book.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include<iostream>
#include<string>
#include <conio.h>
#include <fstream>
#include <sstream>
#include <iomanip>
using namespace std;
class Main
{
private:
string Name;
string Address;
char test;
public:
virtual void getdata()
{
ofstream outfile("TEMP.txt");
cout <<"Enter Name: " ;
cin>>test;
getline(cin, Name); //cin >> Name;
cout << endl;
cout << "Enter Address: ";
getline(cin, Address);// cin >> Address;
outfile << Name
<< endl
<< Address;
}
virtual void setdata()
{
cout << "\n\nName: " << test+Name;
cout << "\nAddress: " << Address;
}
virtual void remove()
{
}
};
//----------------------------------------------------------
class Teacher : public Main
{
private:
int T_Number;
string T_CNIC;
public:
void getdata()
{
ofstream outfile("Teacher.txt");
Main::getdata();
cout << "Enter CNIC: ";
getline(cin,T_CNIC);//cin >> T_CNIC;
cout << "Enter Contact Number: " << endl;
cin >> T_Number;
outfile << T_CNIC
<< endl
<< T_Number;
cout << "Data entered" << endl;
}
void setdata()
{
Main::setdata();
cout << "\nTeacher CNIC: " << T_CNIC;
cout << "\nTeacher Contact Number: " << T_Number;
}
};
//------------------------------------------------------------
class Student : public Main
{
private:
int S_Number;
int S_ID;
public:
void getdata()
{
ofstream outfile("Student.txt");
Main::getdata();
cout << "Enter ID: ";
cin >> S_ID;
cout << "Enter Contact Number: ";
cin >> S_Number;
outfile << S_ID
<< endl
<< S_Number;
cout << "Data entered" << endl;
}
void setdata()
{
Main::setdata();
cout << "\nStudent Unique ID: " << S_ID;
cout << "\nStudent Contact Number: " << S_Number;
}
};
class Employee : public Main
{
private:
int E_Number;
string E_CNIC;
public:
void getdata()
{
ofstream outfile("Employee.txt");
Main::getdata();
cout << "Enter Employee CNIC: ";
getline(cin,E_CNIC);//cin >> E_CNIC;
cout << "Enter Contact Number: ";
cin >> E_Number;
outfile << E_CNIC
<< endl
<< E_Number;
cout << "Data entered" << endl;
;}
void setdata()
{
Main::setdata();
cout << "\nEmployee Unique ID: " << E_CNIC;
cout << "\nEmployee Contact Number: " << E_Number;
}
};
//-----------------------------------------------------------------------------------------
int _tmain(int argc, _TCHAR* argv[])
{
Main* myarr[100];
int var = 0;
int choice;
char input;
start:
printf("===============MAIN MENU===============");
printf("\n[1]Insert\n[2]Search\n[3]Delete\n[4]Exit\n");
printf("=======================================");
printf("\n\nEnter Your Choice: ");
cin >> choice;
switch(choice)
{
case 1:
cout << "\nEnter data for Student or Teacher or Employee (s/t/e)? ";
cin >> input;
do
{
if( input=='t' )
myarr[var] = new Teacher;
else if (input == 'e')
myarr[var] = new Employee;
else
myarr[var] = new Student;
myarr[var++]->getdata();
cout << " Enter another (y/n)? ";
cin >> input;
if(input == 'n')
{
goto start;
}
}
while( input =='y');
for(int j=0; j<var; j++)
myarr[j]->setdata();
cout << endl;
break;
case 2:
return 0;
break;
case 3:
return 0;
break;
case 4:
cout << "Are you sure you want to quit? " << endl;
getch();
break;
default:
cout << "Choose from 1 - 4 ONLY!!" << endl;
goto start;
break;
}
return 0;
}