我有一个实现可运行的java程序。在正文中,我有Thread animator = new Thread();
thenanimator.start();
问题是run()
我的程序的方法没有执行。我错过了什么吗?
问问题
2725 次
2 回答
2
正如你所说的实现可运行的java程序。
在你写的那个类(名字说动画师)身上
Thread animator = new Thread();
animator.start();
如果我没有错
通过可运行的类实例,我认为它会this
在创建线程时
Thread animator = new Thread(this);
animator.start();
于 2012-04-29T05:44:36.510 回答
1
你可以这样试试
public class BackgroundActivity {
/**
* Attempts to execute the user activity.
*
* @return The thread on which the operations are executed.
*/
public Thread doWork() {
final Runnable runnable = new Runnable() {
public void run() {
System.out.println("Background Task here");
}
};
// run on background thread.
return performOnBackgroundThread(runnable);
}
/**
* Executes your requests on a separate thread.
*
* @param runnable
* The runnable instance containing mOperations to be executed.
*/
private Thread performOnBackgroundThread(final Runnable runnable) {
final Thread t = new Thread() {
@Override
public void run() {
try {
runnable.run();
} finally {
}
}
};
t.start();
return t;
}
}
最后是 main 方法中的 doWork() 方法
/**
* @param args
*/
public static void main(String[] args) {
BackgroundActivity ba = new BackgroundActivity();
Thread thread = ba.doWork();
//You can manages thread here
}
希望,它会帮助你。
于 2012-04-29T05:54:14.587 回答