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我想从数据库中提取一个 JSON 字符串并更新一个 textview。我的 Json 字符串如下所示： 

[
    {
        "meaning": "A boy or young man (often as a form of address)",
        "examples": [
            "I read that book when I was a <em>lad</em>",
            "come in, <em>lad</em>, and shut the door"
        ]
    },
    {
        "meaning": "A group of men sharing recreational, working, or other interests",
        "examples": [
            "she wouldn't let him go out with the <em>lads</em> any more"
        ]
    },
    {
        "meaning": "A man who is boisterously macho in his behavior or actions, esp. one who is interested in sexual conquest",
        "examples": [
            "Tony was a bit of a <em>lad</em>âalways had an eye for the women"
        ]
    },
    {
        "meaning": "A stable worker (regardless of age or sex)",
        "examples": []
    }
]


我只想提取“意义”。我该怎么做？

4

1 回答 1

2

首先，这是一个 JSON 数组，meaning里面有很多 s。

你可以像这样迭代它：

JSONArray jarr = new JSONArray(theJsonString);
for (int i = 0; i < jarr.length(); ++i)
{
    JSONObject jCell = jarr.getJSONObject(i);
    String meaning = cell.getString("meaning");
    // set it as text? concatenate the strings?
}

笔记：

  • 为了保持代码清晰，我没有处理异常，请在您的代码中进行。
  • 阅读有关JSON 格式的更多信息。
  • 以下类是 android 的一部分：JSONArray，JSONObject。
  • 值得一读，下次不用问了：）
于 2012-04-29T04:09:34.467 回答