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我已经从 SQLite 数据库创建了一个 ListView，但我一直坚持如何为每个 ListView 项目添加一个侦听器，以便在单击一个项目时我可以显示另一个页面，其中包含有关该项目的更多信息。该数据库只是一个示例。任何帮助，将不胜感激。

public class Database extends ListActivity {

private final String SAMPLE_DB_NAME = "myFriendsDb";
//private final String SAMPLE_TABLE_NAME = "friends";

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);


    ArrayList<String> results = new ArrayList<String>();
    SQLiteDatabase db = null;

    try {
        db =  this.openOrCreateDatabase(SAMPLE_DB_NAME, MODE_PRIVATE, null);

        db.execSQL("CREATE TABLE IF NOT EXISTS people" +
                " (LastName VARCHAR, FirstName VARCHAR," +
                " Country VARCHAR, Age INT(3));");

        db.execSQL("INSERT INTO people" +
                " Values ('Jones','Bob','UK',30);");
        db.execSQL("INSERT INTO people" +
                " Values ('Smith','John','UK',40);");
        db.execSQL("INSERT INTO people" +
                " Values ('Thompson','James','UK',50);");

        Cursor c = db.rawQuery("SELECT FirstName, LastName FROM people", null);

        if (c != null ) {
            if  (c.moveToFirst()) {
                do {
                    String firstName = c.getString(c.getColumnIndex("FirstName"));
                    String lastName = c.getString(c.getColumnIndex("LastName"));
                    results.add("" + firstName + " " + lastName);
                }while (c.moveToNext());
            } 
        }

        this.setListAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1,results));

    } catch (SQLiteException se ) {
        Log.e(getClass().getSimpleName(), "Could not create or Open the database");
    } finally {
        if (db != null) 
            db.execSQL("DELETE FROM people");
            db.close();
    }
}

}

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1 回答 1

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有很多方法可以解决您的问题。一种可能的解决方案是：您只需在 ListActivity 中实现受保护的方法 onListItemClick(ListView l, View v, int position, long id)。 

public class Database extends ListActivity {

    //YOUR CODE ABOVE HERE...

    public static final String SHOWITEMINTENT_EXTRA_FETCHROWID = "fetchRow";
    public static final int ACTIVITY_SHOWITEM = 0; /*Intent request user index*/

    @Override
    protected void onListItemClick(ListView l, View v, int position, long id){
        /*
        position variable holds the position of item you clicked...
        do your stuff here. If you want to send to another page, say another activity
        that shows your stuff, you can always use an intent
        example:
        */
        Intent tmpIntent = new Intent(this, YourActivityForShowingItem.class);
        tmpIntent.putExtra(SHOWITEMINTENT_EXTRA_FETCHROWID, position);
        startActivityForResult(tmpIntent, ACTIVITY_SHOWITEM);

    }
}

或者，您可以使用 getListView() 访问 listActivity 的 ListView，并像使用常规 ListView 对象一样调用侦听器或上下文菜单的设置器。例如，这个使用这种方法设置监听器的函数： 

private void setMyListListener(){
    getListView().setOnItemClickListener(new OnItemClickListener(){
        @Override
        public void onItemClick(AdapterView<?> a, View v, int position, long id){
            /*same fake code as above for calling another activity using an intent:*/
            Intent tmpIntent = new Intent(this, YourActivityForShowingItem.class);
            tmpIntent.putExtra(SHOWITEMINTENT_EXTRA_FETCHROWID, position);
            startActivityForResult(tmpIntent, ACTIVITY_SHOWITEM);
        }
    });
}

This function can be called by your onCreate(...) function afterwards if you want your click listener to be configured the same way for the whole duration of your activity.

于 2012-04-28T02:02:27.300 回答