2

我使用 python 2.7 和 openCV 2.3.1 (win 7)。我尝试打开视频文件：

stream = cv.VideoCapture("test1.avi")
if stream.isOpened() == False:
print "Cannot open input video!"
exit()

但我有警告：

warning: Error opening file (../../modules/highgui/src/cap_ffmpeg_impl_v2.hpp:394)

如果使用摄像机 ( stream = cv.VideoCapture(0))，则此代码有效。关于我做错了什么的任何想法？非常感谢大家！

4

3 回答 3

3

Try using cv.CaptureFromFile() instead.

Copy this code if you must: Watch Video in Python with OpenCV.

于 2012-04-27T16:11:20.210 回答
1

您可以使用 OpenCV (cv2) 的新接口，它是从 c++ 绑定的面向对象的接口。我发现它更容易阅读。

注意：如果你用这个打开图片，fps 没有任何意义，所以图片保持静止。

import cv2
import sys

try:
    vidFile = cv2.VideoCapture(sys.argv[1])
except:
    print "problem opening input stream"
    sys.exit(1)
if not vidFile.isOpened():
    print "capture stream not open"
    sys.exit(1)

nFrames = int(vidFile.get(cv2.cv.CV_CAP_PROP_FRAME_COUNT)) # one good way of namespacing legacy openCV: cv2.cv.*
print "frame number: %s" %nFrames
fps = vidFile.get(cv2.cv.CV_CAP_PROP_FPS)
print "FPS value: %s" %fps

ret, frame = vidFile.read() # read first frame, and the return code of the function.
while ret:  # note that we don't have to use frame number here, we could read from a live written file.
    print "yes"
    cv2.imshow("frameWindow", frame)
    cv2.waitKey(int(1/fps*1000)) # time to wait between frames, in mSec
    ret, frame = vidFile.read() # read next frame, get next return code
于 2014-01-16T14:17:46.527 回答
0

从此答案开始，尝试将.dllOpenCV 安装中的所有文件复制到C:\Python27.

于 2014-03-15T04:43:13.757 回答