0

我需要构建 HTML 页面来显示和组织我的结果。我在哪里放置 HTML？我试过了，我得到了错误。它是否进入 php 脚本？在php脚本之后？前？使困惑。

<?php

if (isset($_POST['Submit'])) {
if (!empty($_POST['reg'])) {

    $record = $_POST['reg'];

    $query = mysql_query("SELECT * FROM reg_add WHERE reg='" . mysql_real_escape_string($record) . "'");
    $result = mysql_num_rows($query);

    if ($result != 0) {

        $row = mysql_fetch_array($query);

        $connect_date = $row['connect_date'];
        $reg = $row['reg'];
        $first_name = $row['first_name'];
        $last_name = $row['last_name'];
        $nickname = $row['nickname'];
        $gender = $row['gender'];
        $birthday = $row['birthday'];
        $home_state = $row['home_state'];
        $national = $row['national'];
        $location = $row['location'];


    } else {
        header("Location: search_error1.php");
        exit;
    }

} else {
    header("Location: search_error2.php");
    exit;
}
}
?>
4

1 回答 1

2

PHP 可嵌入到 HTML 中，因此您可以直接在 php 文件中编写 html 标记。您只需将所有 php 代码放入其中<?php ?>：

<?php
    //php code
?>
<html>
<!-- ... -->
</html>
<?php /* php again */ ?>

PHP 解释器简单地忽略写在 php 标签 ( ) 之外的所有文本，<?php ?>并将其直接写入标准输出。

所以对你来说，它会是这样的：

<?php

// ...

if ($result != 0) {
    while($row = mysql_fetch_array($query)) {
        $connect_date = $row['connect_date'];
        $reg = $row['reg'];
        $first_name = $row['first_name'];
        $last_name = $row['last_name'];
        $nickname = $row['nickname'];
        $gender = $row['gender'];
        $birthday = $row['birthday'];
        $home_state = $row['home_state'];
        $national = $row['national'];
        $location = $row['location'];
?>
  First name: <?php echo $first_name ?><br/>
  Last name: <?php echo $last_name ?><br/>
  ...
<?php
    }
}

// ...

?>
于 2012-04-27T14:17:10.763 回答